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高分求一个汇编语言的完整程序!

2023-07-08 00:11:47
共6条回复
再也不做稀饭了

从键盘输入时间初始值后,用固定时间产生0.1s定时中断,触发时钟记数器记数,并将数值实时送显示器显示。

ORG 0030H

CHK00: MOV SP,#60H

LCALL LEDP

MOV DPTR,#CLOCK

MOV R0,DPL

MOV R1,DPH

MOV DPTR,#000BH

MOV A,#02H

MOVX @DPTR,A

INC DPTR

MOV A,R1

MOVX @DPTR,A

INC DPTR

MOV A,R0

MOVX @DPTR,A

LCK0: LCALL LCK0

LCALL PTDS0

MOV TMOD,#01H

ORL IE,#82H

MOV TL0,#0B7H

MOV TH0,#3CH

MOV 23H,#00H

SETB TR0

L005: LCALL DIS

LCALL PTDS0

SJMP L005

PTDS0: MOV R0,#79H

MOV A,22H

ACALL PTDS

MOV A,21H

ACALL PTDS

MOV A,20H

ACALL PTDS

RET

PTDS: MOV R1,A

ACALL PTDS1

MOV A,R1

SWAP A

PTDS1: ANL A,#0FH

MOV @R0,A

INC R0

RET

LOCK: MOV TL0,#0B7H

MOV TH0,#3CH

PUSH PSW

PUSH ACC

SETB 0D3H

INC 23H

MOV A,23H

CJNE A,#0AH,DONE

MOV 23H,#00H

MOV A,22H

INC A

DA A

MOV 22H,A

CJNE A,#60H,DONE

MOV 22H,#00H

MOV A,21H

INC A

DA A

MOV 21H,A

CJNE A,#60H,DONE

MOV 21H,#00H

MOV A,20H

INC A

DA A

MOV 20H,A

CJNE A,#24H,DONE

MOV 20H,#00H

DONE: POP ACC

POP PSW

RETI

ORG 0D59H

SSEE: SETB RS1

MOV R5,#05H

SSE2: MOV 30H,#20H

MOV 31H,#7EH

MOV R7,#06H

SSE1: MOV R1,#0DDH

MOV A,30H

MOVX @R1,A

MOV R0,31H

MOV A,@R0

MOV DPTR,#0DDFFH

MOVC A,@A+DPTR

MOV R1,#0DCH

MOVX @R1,A

MOV A,30H

RR A

MOV 30H,A

DEC 31H

MOV A,#0FFH

MOVX @R1,A

DJNZ R7,SSE1

DJNZ R5,SSE2

CLR RS1

RET

DDFF: DB 0C0H,0F9H,0A4H,0B0H,99H,92H

DB 82H,0F8H,80H,90H,0F8H,80H,90H

DB 88H,83H,bC6H,0A1H,86H,8EH

DB 0FFH,0CH,89H,0DEH

ORG 038EH

X3: MOV R4,A

MOV R0,#50H

MOV A,@R0

MOV R1,A

MOV A,R4

MOV @R1,A

CLR A

POP DPH

POP DPL

MOVC A,@A+DPTR

INC DPTR

CJNE A,01H,X30

DEC R1

CLR A

MOVC A,@A+DPTR

X31: MOV @R0,A

INC DPTR

PUSH DPL

PUSH DPH

RET

X30: DEC R1

MOV A,R1

SJMP X31

X2: MOV R6,#50H

X0: ACALL XLE

JNB ACC,5,XX0

DJNZ R6,X0

MOV R6,#20H

MOV R0,#50H

MOV A,@R0

MOV R0,A

MOV A,@R0

MOV R7,A

MOV A,#10H

MOV @R0,A

X1: ACALL XLE

JNB ACC,5,XX1

DJNZ R6,X1

MOV A,R7

MOV @R0,A

SJMP X2

XX1: MOV R6,A

MOV A,R7

MOV @R0,A

MOV A,R6

XX0: RET

XLE: ACALL DIS

ACALL KEY

MOV R4,A

MOV R1,#48H

MOV A,@R1

MOV R2,A

INC R1

MOV A,@R1

MOV R3,A

MOV A,R4

XRL A,R3

MOV R3,04H

MOV R4,02H

JZ X10

MOV R2,#88H

MOV R4,#88H

X10: DEC R4

MOV A,R4

XRL A,#82H

JZ X11

MOV A,R4

XRL A,#0EH

JZ X11

MOV A,R4

JZ X12

MOV R4,#20H

DEC R2

SJMP X13

X12: MOV R4,#0FH

X11: MOV R2,04H

MOV R4,03H

X13: MOV R1,#48H

MOV A,R2

MOV @R1,A

INC R1

MOV A,R3

MOV @R1,A

MOV A,R4

JB ACC,5,X113

JB ACC,4,X113

MOV DPTR,#LS3

MOVC A,@A十DPTR

X113: RET

LS3: DB 07H,04H,08H,05H,09H,06H,0AH

DB 0BH,01H,00H,02H,0FH,03H,0EH

DB 0CH,0DH

DIS: PUSH DPH

PUSH DPL

SETB RS1

MOV R0,#7EH

MOV R2,#20H

MOV R3,#00H

MOV DPTR,#LS0 ,

LS2: MOVA,@R0

MOVC A,@A+DPTR

MOV R1,#0DCH

MOVX @R1,A

MOV A,R2

INC R1

MOVX @R1,A

LS1: DJNZ R3,LS1

CLR C

RRC A

MOV R2,A

DEC R0

JNZ LS2

MOVX @R0,A

DEC R0

CPL A

MOVX @R0,A

CLR RS1

POP DPL

POP DPH

RET

LS0: DB 0C0H,0F9H,0A4H,0B0H,99H,92H

DB 82H,0F8H,80H,90H,88H,83H,0C6H

DB 0A1H,86H,8EH,0FFH,0CH,89H

DB 7FH,0BFH

KEY: SETB RS1

MOV R2,#0FEH

MOV R3,#08H

MOV R0,#00H

LP1: MOV R1,#0DDH

MOV A,R2

MOVX @R1,A

RL A

MOV R2,A

INC R1

MOVX A,@R1

CPL A

ANL A,#0FH

JNZ LP0

INC R0

DJNZ R3,LP1

XP33: MOV A,#20H

XP3: MOV R2,A

CLR A

MOV R1,#0DDH

MOVX @R1,A

MOV A,R2

CLR RS1

RET

LP0: CPL A

JB ACC.0,XP0

MOV A,#00H

SJMP LPP

XP0: JB ACC.1,XP1

MOV A,#08H

SJMP LPP

XP1: JB ACC,2,XP2

MOV A,#10H

SJMP LPP

XP2: JB ACC.3,XP33

MOV A,#18H

LPP: ADD A,R0

SMP XP3

LEDP: MOV 50H,#7EH

MOV A,#10H

MOV R0,#79H

1EDS: MOV @R0,A

INC R0

CJNE R0,#7EH,1EDS

INC A

MOV @R0,A

MOV A,#20H

MOV 48H,A

MOV 49H,A

RET

END

牛云

assume cs:codesg

data segment

db "1975","1976","1977","1978","1979","1980","1981","1982","1983"

db "1984","1985","1986","1987","1988","1989","1990","1991","1992"

db "1993","1994","1995"

dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514

dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000

dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226

dw 11542,14430,15257,17800

data ends //原公司数据

table segment

db 16 dup(0)

table ends //定义16字节数据空间用于暂存对公司数据的相关转换

codesg segment

start:mov ax,data

mov es,ax //设原数据在es段

mov ax,table

mov ds,ax //设转换为要显示在屏幕上的数据的空间为数据段

mov dh,3

mov dl,10 //初始化在3行10列显示第一个数据

mov di,0 //读取双字单元数据的变址

mov si,0 //要显示的数据偏移地址的首地址

mov bp,0 //读取字单元数据的变址

call clear //调用清屏子程序,先清空屏幕

mov cx,21 //程序下面将循环21次,每次显示公司一条记录

main:push cx

mov cl, //显示在屏幕上字符的颜色

mov ax,es:[di]

mov ds:[0],ax

mov ax,es:2[di]

mov ds:[2],ax

call show_str //以上实现年份的字段的显示

add dl,15 //列数增加15,拉开距离,以便显示下一字段

push dx

mov ax,es:84[di]

mov dx,es:86[di]

call dtoc

pop dx

call show_str //以上实现总收入字段的显示

add dl,15 //同上,改变列的显示位置

push dx

mov ax,es:168[bp]

mov dx,0

call dtoc

pop dx

call show_str //以上实现雇员数字段的显示

add dl,15 //同上,改变列的显示位置

push dx

mov ax,es:84[di]

mov dx,es:86[di]

mov bx,es:168[bp]

div bx

mov dx,0

call dtoc

pop dx

call show_str //以上实现人平收入字段的显示

add bp,2

add di,4

inc dh //行数加1,实现换行准备显示下一条记录

mov dl,10 //重设列数为10,准备显示下一条记录,并对齐上一条

pop cx

loop main //返回main,去显示下一条记录

mov ax,4c00h

int 21h

dtoc:push ax //以下是双字型转十进制字符串的子程序

push bx

push cx

push dx

push si

push di

mov bx,0

push bx

mov di,1

s:mov cx,10

call divdw

mov bx,cx

mov cx,ax

add bl,30h

push bx

inc di

jcxz oka

jmp short s

oka:mov cx,dx

jcxz ok

jmp short s

ok:mov cx,di

oo:pop [si]

inc si

loop oo

pop di

pop si

pop dx

pop cx

pop bx

pop ax

ret

show_str:push ax //以下是字符串显示的子程序

push bx

push cx

push dx

push es

push si

mov ax,0b800h

mov es,ax

mov al,160

mul dh

mov bx,ax

mov al,2

mul dl

add bx,ax

mov ch,0

s1:push cx

mov cl,[si]

jcxz ok1

mov es:[bx],cl

pop cx

mov es:[bx+1],cl

inc si

add bx,2

jmp short s1

ok1:pop cx

pop si

pop es

pop dx

pop cx

pop bx

pop ax

ret

divdw:push bx //以下是防除法溢出子程序

mov bx,ax

mov ax,dx

mov dx,0

div cx

push ax

mov ax,bx

div cx

mov cx,dx

pop dx

pop bx

ret

clear:push ax //以下是清空屏幕的子程序

push es

push bx

push cx

mov ax,0b800h

mov es,ax

mov bx,0

mov cx,2000

cls:mov word ptr es:[bx],0720h

add bx,2

loop cls

pop cx

pop bx

pop es

pop ax

ret

codesg ends //代码结束

end start //OK!大功告成...

慧慧

键盘加led显示的程序

dis_data data 40h ;显示数据首地址

key_hold bit 20h.0

ORG 0000H

JMP START

ORG 0100H

START:

MOV SP,#60H

MOV dis_data,#00H

MOV dis_data+1,#01H

MOV dis_data+2,#02H

MOV dis_data+3,#03H ;显示数据初始化

;主程序

MAIN:

CALL DISPLAY

CALL KEY_WORK

JMP MAIN

;-------------------------显示子程序---------------------------

DISPLAY:

MOV R2,#0FEH

MOV R1,#dis_data

DIS0:

MOV A,@R1

MOV DPTR,#TAB

MOVC A,@A+DPTR

MOV P1,A

INC R1

MOV P0,R2

MOV A,R2

RL A

MOV R2,A

CALL DELAY ;调延时子程序

CJNE R1,#44H,DIS0

RET

;-------------------------延时子程序---------------------------

DELAY: MOV R7,#02H

DL: MOV R6,#0FFH

DL6: DJNZ R6,DL6

DJNZ R7,DL

RET

;-----------------------------------------------------------

KEY_WORK:

PUSH ACC

PUSH PSW

KEY_SCAN:

MOV P2,#0FFH

MOV A,P2

CJNE A,#0FFH,KEYHIT0

CLR key_hold ;键释放

JMP RETT

KEYHIT0:

CALL DL10MS ;防抖动

MOV P2,#0FFH

MOV A,P2

CJNE A,#0FFH,KEYHIT1

CLR key_hold ;键释放

JMP RETT

KEYHIT1:

JB key_hold,RETT ;键未释放,返回

SETB key_hold ;新键按下

JNB ACC.0,KEY0HIT

JNB ACC.1,KEY1HIT

JNB ACC.2,KEY2HIT

JNB ACC.3,KEY3HIT

JNB ACC.4,KEY4HIT

JNB ACC.5,KEY5HIT

JNB ACC.6,KEY6HIT

JNB ACC.7,KEY7HIT

JMP RETT

KEY0HIT: ;键1按下

INC dis_data

MOV A,#0AH

CJNE A,dis_data,RETT

MOV dis_data,#00H

JMP RETT

KEY1HIT: ;键2按下

INC dis_data+1

MOV A,#0AH

CJNE A,dis_data+1,RETT

MOV dis_data+1,#00H

JMP RETT

KEY2HIT: ;键3按下

INC dis_data+2

MOV A,#0AH

CJNE A,dis_data+2,RETT

MOV dis_data+2,#00H

JMP RETT

KEY3HIT: ;键4按下

INC dis_data+3

MOV A,#0AH

CJNE A,dis_data+3,RETT

MOV dis_data+3,#00H

KEY4HIT:

DEC dis_data ;键5按下

MOV A,#0ffh

CJNE A,dis_data,RETT

MOV dis_data,#09H

JMP RETT

KEY5HIT:

DEC dis_data+1 ;键6按下

MOV A,#0ffh

CJNE A,dis_data+1,RETT

MOV dis_data+1,#09H

JMP RETT

KEY6HIT:

DEC dis_data+2 ;键7按下

MOV A,#0ffh

CJNE A,dis_data+2,RETT

MOV dis_data+2,#09H

JMP RETT

KEY7HIT:

DEC dis_data+3 ;键8按下

MOV A,#0ffh

CJNE A,dis_data+3,RETT

MOV dis_data+3,#09H

RETT:

POP ACC

POP PSW

RET

;*********************

;键盘仿抖延时延时

;*********************

DL10MS:

MOV R4,#20

DELMS:

CALL DISPLAY

DJNZ R4,DELMS

RET

;将延时程序换成下面的程序看看会有什么样的变化,为什么?

DL10MS11:

MOV R4,#100

DEL11:

MOV R5,#250

NOP

NOP

DJNZ R5,$

DJNZ R4,DEL11

RET

;-------------------------LED显示码表--------------------------

TAB: DB 0c0H, 0f9H, 0a4H, 0b0H, 99H, 92H

; 0 1 2 3 4 5

; 00H 01H 02H 03H 04H 05H

;

DB 82H, 0f8H, 80H, 90H, 88H, 83H

; 6 7 8 9 A b

; 7DH 07H 08H 09H 0AH 0BH

;

DB 0c6H, 0a1H, 86H, 8eH, 8cH, 0c1H

; C D E F P U

; 0CH 0DH 0EH 0FH 10H 11H

;

DB 89H, 0c7H,0bfH, 91H,00H,0ffH

; H L - y ON OFF

; 12H 13H 14H 15H 16H 17H

;

DB 92H, 77H, 8bH, 0afH, 0a3H, 0a1H

; S t h r o d

; 18H 19H 1AH 1BH 1CH 1DH

;

DB 0f0H, 0FH, 8bH, 0afH, 0a3H, 0a1H

; S t h r o d

; 1EH 1FH 20H 21H 22H 23H

END

ardim

已发送。

wpBeta

发到你的邮箱了,,看看合适不合适……

snjk

已发

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2023-07-07 20:47:453

Is That You? 歌词

歌曲名:Is That You?歌手:Bill Frisell专辑:Is That You?Bow Wow - Is That You (P.Y.T)Im Looking for thatpretty young thangup in the spot, looking hot playin` no gamesAnd she steady tryina get it crunk right from the jumpand she playin` no games.that you Shawty? (yea thats me)Did you come here to party? (Yes indeed)Ha But could you drop it down lowwhen its time to get lowif so baby girl lets go.(Come and get it boy)They say I act old, but I got that old man gameCause I stay tryina find me a pretty young thangthat I call anytime if she ready to hangand if sun"it jump off she be ready to bangI like `em fresh outta high schooljust about to graduate short shirtsed`day tryina show they little shapelow cut jump jeans lugz on hea feetneighborhood girl but she love the streetsIn a party she da main one doin dat right thurrEv"time hea jam drop hands up in the airr.And she aint thinkin you, she aint thinkin bout hea hurrAnd if you ballin homie she dont even really currShe got her mind set on what she wanna doAnd she aint come alone she got her whole little crew.Her P.Y.T"s that"ll make ya head spinEry nigga in the club tryina get inIm Looking for thatpretty young thangup in the spot, looking hot playin` no gamesAnd she steady tryina get it crunk right from the jumpand she playin` no games.that you Shawty? (yea thats me)Did you come here to party? (Yes indeed)Ha But could you drop it down lowwhen its time to get lowif so baby girl lets go.(Come and get it boy)They got a whole lot of attituderap is all that they listen tostays in the sweet tryina find somthin newcustom ipods with the rhinestonesnextel camara phones with all the hot ringtones.Light skin til black little PYT"sboricua mami"s that like to eat Mickey D"salways into sumthin like NWAgota little bittie frame but home she dont playYou know a gyrl is the reason that a nigga wanna stuntAnd im weak for em homie I aint even gon frontSee most young nigga"s like em oldernot me spot they spot me like in the summerI run up hit them with that Moss A gamelike "Baby wuz ya phone numba? Were ya live at?Shawdy what part of town? Cuz I just wanna be down!"Im Looking for thatpretty young thangup in the spot, looking hot playin` no gamesAnd she steady tryina get it crunk right from the jumpand she playin` no games.that you Shawty? (yea thats me)Did you come here to party? (Yes indeed)Ha But could you drop it down lowwhen its time to get lowif so baby girl lets go.(Come and get it boy)Pretty Young Thang repeat after mesay Nah nanana "Nah nanana"Nah nanana "Nah nanana"say pretty young thangs repeat after mesay Nah nanana "Nah nanana"Nah nanana "Nah nanana"Im Looking for thatpretty young thangup in the spot, looking hot playin` no gamesAnd she steady tryina get it crunk right from the jumpand she playin` no games.that you Shawty? (yea thats me)Did you come here to party? (Yes indeed)Ha But could you drop it down lowwhen its time to get lowif so baby girl lets go.(Come and get it boy)http://music.baidu.com/song/1061230
2023-07-07 20:47:521

c语言输入一串字母 输出字母数字 其它字符的个数

对于这个问题,不需要存到数组。按照如下流程即可:1 输入一个字符,对该字符进行判断:a) 如果是数字,则数字累加器加一。b) 如果是字母,则字母累加器加一。c)如果是换行,则结束统计(以换行为结束符。如需其他结束符,根据需要更改判断)。2输出结果。代码:#include <stdio.h>int main(){int c, n, i;c=n=0;while(1){i = getchar();if(i>="0" && i <= "9") n++;else if((i>="a" && i <= "z")||(i>="A" && i <= "Z"))c++;else if(c==" ") break;}printf("数字%d个,字母%d个 ", n,c);return 0;}
2023-07-07 20:48:021

题目如下 #includestruct s {int a,b;} data[2]=10,100,20,200}; main() { struct s p=da...

struct s {int a,b;} data[2]={10,100,20,200}; 定义了一个数组,data[1]中的a未20b为200然后p=a[1],把a[1]的值赋给p
2023-07-07 20:48:092

C语言编程代码

#include<stdio.h>int main(){ int date=0,da=0,xiao=0; char c; c=getchar(); while(c!="!") { if(c>="a"&&c<="z") xiao++; if(c>="A"&&c<="Z") da++; if(c>="0" &&c<="9") date++; c=getchar(); // 输入多个字符} printf("xiao=%d,da=%d,date=%d ",xiao,da,date); return 0;}
2023-07-07 20:48:205

数据集合处理(c++处理)

/*要求:1.集合元素不超过100个。2.集合用数组表示(数组预先定义大一些)。功能有:1.程序初始运行时任意输入一批初始数放入集合(可少可多,不少于5个,不超过30个)。2对该批数排序存放。程序完成前两步后,通过循环可以不断选择下面的某项功能执行(用提示语句列出菜单,通过读入某变量值,switch判断该变量,如接受到1表示执行第一项,依次类推,某项功能执行完可以返回菜单,也可退出系统):3.任意插入一个数到排好序的集合中,保持集合依然有序。4.在集合中删除一个元素。5.查询某个值是否在集合中(该数由键盘输入)。6.求出该数据集合的最大值和最小值及所在位置。7.找出数据集合中的所有素数。*/#include<iostream.h>#include<windows.h>/*charmenu[][100]={" **************************************","请选择操作:","1:输出现有数据;","2:插入一个数据;","3:删除一个数据;","4:查找指定数据;","5:找出数组中最大值","6:找出数组中最小值;","0:退出","*************************************** "};*/charmenu[]=" *************************************** 请选择操作: 1:输出现有数据; 2:插入一个数据; 3:删除一个数据; 4:查找指定数据; 5:找出数组中最大值; 6:找出数组中最小值; 0:退出。 *************************************** ";classArry{private:intarry[110];intnum;public:Arry();//用随机产生的数初始化数组并排序voidInsert(intia);//插入一个数voidShow();//输出现有数组voidDelete(intda);//删除指定的数voidFind(intfa);//查找指定的数voidFindMax();//找出最大数voidFindMin();//找出最小数};Arry::Arry(){num=30;inttemp=0;for(inti=0;i<110;i++)if(i<30)arry[i]=rand()/100;elsearry[i]=0;for(i=0;i<num-1;i++)for(intj=0;j<num-i-1;j++)if(arry[j]>arry[j+1]){temp=arry[j];arry[j]=arry[j+1];arry[j+1]=temp;}}voidArry::Insert(intia){inti=0;if(arry[0]>=ia){for(intj=num;j>0;j--)arry[j]=arry[j-1];arry[0]=ia;num++;}else{while(arry[i]<ia&&i<num)i++;for(intj=num;j>i;j--)arry[j]=arry[j-1];arry[j]=ia;num++;}}voidArry::Show(){cout<<"现有数据为: ";for(inti=0;i<num;i++){cout<<arry[i]<<" ";if((i+1)%5==0)cout<<endl;}cout<<endl;}voidArry::Find(intfa){intf=0;for(inti=0;i<num;i++)if(arry[i]==fa){f=1;cout<<"数组中第"<<i+1<<"个数是";cout<<arry[i]<<endl;}if(f==0)cout<<"数组中没有找到指定的数!"<<endl;}voidArry::Delete(intda){ints=0;for(inti=0;i<num;i++)if(arry[i]==da){for(intj=i;j<num-1;j++)arry[j]=arry[j+1];arry[j]=0;i--;num--;s++;}if(s)cout<<"删除了"<<s<<"个数据!"<<endl;elsecout<<"数组中没有找到指定的数!"<<endl;}voidArry::FindMax(){intp=0;intmax=arry[0];for(inti=1;i<num;i++)if(arry[i]>=max){max=arry[i];p=i;}cout<<"数组中最大数据是:"<<max<<endl;cout<<"在数组中的位置是第"<<p+1<<"个"<<endl;}voidArry::FindMin(){intp=0;intmin=arry[0];for(inti=1;i<num;i++)if(arry[i]<=min){min=arry[i];p=i;}cout<<"数组中最小数据是:"<<min<<endl;cout<<"在数组中的位置是第"<<p+1<<"个"<<endl;}voidmain(){Arrya;intchoice=0;intdata=0;while(1){//for(inti=0;i<10;i++)//cout<<menu[i]<<endl;cout<<menu;cin>>choice;switch(choice){case0:exit(1);break;case1:a.Show();break;case2:cout<<"输入要插入的数据:";cin>>data;a.Insert(data);break;case3:cout<<"输入要删除的数据:";cin>>data;a.Delete(data);break;case4:cout<<"输入要查找的数据:";cin>>data;a.Find(data);break;case5:a.FindMax();break;case6:a.FindMin();break;default:cout<<"操作错误! ";break;}}}
2023-07-07 20:48:373

c语言:输入十个数,求最大值,最小值,平均值

以下是一个简单的 C 语言程序,可以用于输入十个数,并求出它们的最大值、最小值和平均值:```c#include <stdio.h>int main() { int i; double sum = 0.0, max, min, num; // 输入第一个数,并将其作为最大值和最小值的初始值 printf("请输入第1个数: "); scanf("%lf", &num); max = min = num; sum += num; // 循环输入剩余9个数,并更新最大值、最小值和总和 for (i = 2; i <= 10; i++) { printf("请输入第%d个数: ", i); scanf("%lf", &num); if (num > max) { max = num; } if (num < min) { min = num; } sum += num; } // 输出结果 printf("最大值为: %.2f ", max); printf("最小值为: %.2f ", min); printf("平均值为: %.2f ", sum / 10); return 0;}```在这个程序中,我们使用了一个 `for` 循环来输入十个数,并分别更新最大值、最小值和总和。需要注意的是,我们在循环开始时已经输入了第一个数,并将其作为最大值和最小值的初始值。最后,我们输出计算得到的最大值、最小值和平均值。需要注意的是,在计算平均值时,我们使用了总和除以10的方式来求解,因为本程序中输入了恰好十个数。如果输入的数目不是十个,应该相应地调整计算平均值的方式。
2023-07-07 20:48:473

程序运行中da变量精度不够,后面总是0.0000

没什么问题啊,除了 第7行 // int ;
2023-07-07 20:49:072

编写函数求出二维整型数组中元素的最大值及其下标号。

//你的错误太多,给你个新的#include<stdio.h>#include<stdlib.h>void da(int a[][4],int n){int i,j,row=0,col=0,max=a[0][0];for(i=0;i<n;i++)for(j=0;j<4;j++){if(a[i][j]>max){max=a[i][j];row=i;col=j;}}printf("最大值:a[%d][%d]=%d ",row,col,max); }int main(){int i,j,n,a[10][4];scanf("%d",&n);for(i=0;i<n;i++)for(j=0;j<4;j++)scanf("%d",&a[i][j]);da(a,n);return 0; }
2023-07-07 20:49:173

单片机汇编程序实现DA转换,用DAC0832芯片实现

这是一个仿真实例,可以参考一下,试试。
2023-07-07 20:49:383

关于单片机DA指令

正确答案,可见:http://zhidao.baidu.com/question/151649564
2023-07-07 20:49:462

51低端单片机没有PWM,怎么用DA做呼吸灯???

AD呼吸灯是什么?如果需要51输出PWM的话可以使用定时器,里89C52为例推荐是定时器T2作为发生器,可以作为ADC0809这样AD的工作频率
2023-07-07 20:49:542

我想知道单片机的蜂鸣器音乐程序中断是如何响应的?从main主程序中如何到中断程序?具体步骤是啥?谢谢!

挺简单啊,时间一到就进入中断,中断完再回到主程序
2023-07-07 20:50:032

C++实现:6.编写程序,统计文本文件中大写英文字母,小写英文字母和数字的个数。

#include<stdio.h>#include<stdlib.h>#define NULL 0void main(){FILE *fp1=NULL,*fp2=NULL;int xiao=0,da=0,shu=0,all[26],i;char ch;fp1=fopen("你要读取的文本名字.txt","r");//要把你要读取的文本放在程序所在的地方fp2=fopen("你想要保存位的文本的名字.txt","w");if(fp1==NULL) { printf("Can not open "); exit(0); }if(fp2==NULL) { printf("Can not open "); exit(0); }for(i=0;i<26;i++) all[i]=0;ch=fgetc(fp1);while(ch!=EOF) { if((ch>=65)&&(ch<=90)) { da++; all[ch-65]++; } else if((ch>=97)&&(ch<=122)) { xiao++; all[ch-97]++; } else if((ch>=48)&&(ch<=57)) { shu++; } ch=fgetc(fp1); }printf("小写字母个数为%d 大写字母个数为%d 数字个数为%d ",xiao,da,shu);fprintf(fp2,"小写字母个数为%d 大写字母个数为%d 数字个数为%d ",xiao,da,shu);for(i=0;i<26;i++)fprintf(fp2,"%c=%d ",i+65,all[i]);fclose(fp1);fclose(fp2);}vc++6.0运行成功
2023-07-07 20:50:112

有一首女生唱的英文歌,中间停顿部分是啦啦啦 啦啦啦啦啦啦啦,哼了很长一段,整首歌节奏感很强,求歌名

霹雳英雄布袋戏、不谢
2023-07-07 20:50:1914

编写程序,输入一维数组的10个元素,并将最小值与第1个数交换,最大值与最后一个数交换,然后输出交换后的1

#include<stdio.h>void main(){ int i,max,min,da,xiao,a[10]; printf("请输入任意10个整数 "); for(i=0;i<10;i++) { scanf("%d",&a[i]); } max=a[0]; min=a[0]; for(i=1;i<10;i++) { if(a[i]>max) { max=a[i]; da=i;} if(a[i]<min){ min=a[i]; xiao=i;} } a[da]=a[0]; a[xiao]=a[9]; a[0]=max; a[9]=min; for(i=0;i<10;i++) printf("%d ",a[i]);}
2023-07-07 20:51:032

c++数组复制的函数

#include<iostream>#define max 100using namespace std;class bank{ int top; char date[max][10]; float money[max]; float rest[max]; static float sum;public: bank(){top=0;} void bankin(char d[],float m) { // 数组的名称即可作为指针使用 strcpy(date[top],d); money[top]=m; sum=m+sum; rest[top]=sum; top++; } void bankout(char d[],float m) { strcpy(date[top],d); money[top]=-m; sum=sum-m; rest[top]=sum; top++; } void disp() { int i; printf(" 日期 存入 取出 余额 "); for(i=0;i<top;i++) { printf("%8s ",date[i]); if(money[i]<0) printf("%6f ",-money[i]); else printf("%f ",money[i]); printf("%6d ",rest[i]); } }};float bank::sum=0;void main(){ bank obj; obj.bankin("2002.2.5",1000); obj.bankin("2001.3.2",2000); obj.bankout("2001.4.1",500); obj.bankout("2001.4.5",800); obj.disp();}
2023-07-07 20:51:149

c++程序编写问题2

h> void fun(int a[][34],int n) { int i,j; for(i=0;i<n;i++) for(j=0;j<=i;j++) { if(i==j) a[i][j]=1; else if(j==0) a[i][j]=1; else a[i][j]=a[i-1][j-1]+a[i-1][j]; } } int main() { int i,j,k,n; int a[34][34]; k=1; while(scanf("%d",&n)==1) // 输入你要显示的行数,如1,2,3,4,... { fun(a,n); printf("Case %d: ",k++); for(i=0;i<n;i++) { for (j = 0; j < n - i; j ++) printf(" "); for(j=0;j<=i;j++) { if(j==i) printf("%d",a[i][j]); else printf("%d ",a[i][j]); } printf(" "); } printf(" "); } return 0; }第2个:#include<stdio.h>struct d{ int year; int month; int day;}data;int main(){ int m(struct d da); int n; printf("输入日期:"); scanf("%d%d%d",&data.year,&data.month,&data.day); n=m(data); printf("该日期是%d年第%d天",data.year,n); return 0;}int m(struct d da){ if(da.month==1) return da.day; int i,sum=0,mo[12]=; for(i=0;i<da.month-1;i++) { sum=sum+mo[i]; } sum+=da.day; if(da.year%400==0||da.year%4==0&&da.year%100!=0) if(da.month>2) sum++; return sum;}
2023-07-07 20:51:311

采用表尾插入元素创建一个单链表。

#include<iostream> using namespace std; template <typename T>class List;template <typename T>class Node { friend class List<T>;private: T data; Node<T>* next;public: Node(){data=NULL;next=NULL;} Node(T& da) {data =da;next=NULL;} Node(T& da,Node<T>* ne) {data=da;next = ne};};template <typename T>class List{private: int length; Node<T>* head;//头结点,其next节点为第一个节点 Node<T>* last;//指向最后一个结点的指针public: List(); void insert (T& data); void remove (T data); int getLength() const{return length;}; void print () const; void reverse();};template <typename T>List<T>::List(){ length = 0; head = new Node<T>(); last = head;}template <typename T>void List<T>::insert(T &data){ last = last ->next =new Node<T>(data); length++;}template <typename T>void List<T>::remove(T data){ Node<T>* current = head; while (current->next!=NULL) { if(current->next->data==data) { Node<T>* temp = current->next; current->next = current->next->next; delete temp; length--; } else current = current->next; }}template <typename T>void List<T>::print() const{ Node<T>* current =head; while (current->next!=NULL) { current = current->next; cout<<current->data<<" "; }}template <typename T>void List<T>::reverse(){ Node<T>* temp1;//利用三个临时指针降List中每个结点的next倒向 Node<T>* temp2; Node<T>* temp3; last = head->next; temp1 = head; temp2 = temp1->next; while(temp2!=NULL) { temp3 = temp2->next; temp2->next = temp1; temp1 = temp2; temp2 = temp3; }//倒向完毕 last->next = NULL;//重新设置head和last head->next = temp1;}int main ()//测试代码{ List<int> one; int i1=34,i2=89,i3=232; one.insert(i1); one.insert(i1); one.insert(i1); one.insert(i1); one.insert(i2); one.insert(i3); one.print(); cout<<endl; one.reverse(); one.print(); cout<<endl; one.remove(34); one.print();}我用的是vc2008,应该没问题,都按照要求了
2023-07-07 20:51:393

c语言,一个简单问题,求教

#include <stdio.h>#include <stdlib.h>#include <string.h>struct A{ int a; char b[10]; double c;};struct A f(struct A t);void main(){ struct A a = {1001,"ZhangDa",1098.0}; a = f(a); printf("%d,%s,%6.1f ",a.a,a.b,a.c);}struct A f(struct A t){ t.a=1002; strcpy(t.b,"ChangRong"); t.c=1202.0; return t;}
2023-07-07 20:51:488

C++实现一个Date类 用日/月/年的格式输出日期,设置日期操作;在Date类基础上,实现一个可以进行加天数操作

#include<iostream.h>static int dys[]={31,28,31,30,31,30,31,31,30,31,30,31};class date{ int yr,mo,da;public: date(int y,int m,int d) { yr=y; mo=m; da=d; } date() {} void disp() { cout<<yr<<"年"<<mo<<"月"<<da<<"日"<<endl; } date operator + (int day) { date dt=*this; day+=dt.da; while (day>dys[dt.mo-1]) { day-=dys[dt.mo-1]; dt.mo++; if (dt.mo==13) { dt.mo==1; dt.yr++; } } dt.da=day; return dt; }};void main(){ int y,m,d,a,b; cout<<"输入年月日:"; cin>>y>>m>>d; date d1(y,m,d),d2,d3; d1.disp(); cout<<"输入要加的天数(整数):"; cin>>a; d2=d1+a; d2.disp();}
2023-07-07 20:52:051

The main streets _____ shining in the sun. A.seemed B.are seemed C.are seeming D.has seemed 选哪个

Aseem不用于进行时态和被动语态中
2023-07-07 20:52:123

c语言编程单片机与proteus仿真问题(DA转换)?

双击led,在mode type的属性里调成digital
2023-07-07 20:52:223

#include "stdio.h" main() { int x=8; for(;x>0;x--) { if(x%3) {printf(%d,,x--}

#include <stdio.h>void main() { int x=8; for(;x>0;x--) { if(x%3) { printf("%d ",x--); } }}不知道你说什么意思,帮你完整了下
2023-07-07 20:52:432

在函数中为啥使用结构体指针数组,为其赋值赋不上,(申请了空间),在main函数中可以赋值

你的空间没释放!!free(s);free(root);
2023-07-07 20:53:012

123.有以下程序 #include main() { int a=0,b=0,c=0,d=0; (a++ && b++) ? c++ : d++; printf(

首先,判断(a++&&b++)这个条件,这个条件中又首先判断a++,得到结果为假(由于是后置自增运算符,所以a在判断的时候为0,判断之后为1)。&&运算中,只要有一个条件为假,则整个条件为假,所以程序不再判断b++这个条件,并且将(a++&&b++)这个条件判定为假。所以程序执行冒号后面的d++。所以a=1,b=0,c=0,d=1。所以答案选D
2023-07-07 20:53:101

二级C++考试复习习题集

应付考试,首选谭浩强的书啦~
2023-07-07 20:53:192

c语言问题

若有高手,望详细解答,小弟也很小知道,谢谢
2023-07-07 20:53:293

关于C语言中的while(1)的应用对程序执行的影响

不加while(1)则程序会不停地循环执行整个main()函数,加了的话就会停在while(1)处了。
2023-07-07 20:53:382

C语言编写一万年历系统!高分!

你是沈师软件大一的吧???TC 2.0 /* welcome to use the WanNianLi system! Copyright @ 2005 KongXinCai All rights reserved!:):):)*/ #include<stdio.h> #include<stdlib.h> char* month_str[]={"January","February","March","April","May","June","July","August","September","October","November","December"}; char* week[]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"}; int IsLeapYear(int year) /*find out the year is leap year or not*/ { if((year%4==0&&year%100!=0)||(year%400==0)) return 1; else return 0; } int month_day(int year,int month) { int mon_day[]={31,28,31,30,31,30,31,31,30,31,30,31}; if(IsLeapYear(year)&&month==2) return 29; else return(mon_day[month-1]); } int DaySearch(int year,int month,int day) /*search what day this day is*/ { int c=0; float s; int m; for(m=1;m<month;m++) c=c+month_day(year,m); c=c+day; s=year-1+(float)(year-1)/4+(float)(year-1)/100+(float)(year-1)/400-40+c; return ((int)s%7); } int PrintAllYear(int year)/*print the all year*/ { int temp; int i,j; printf(" %d Calander ",year); for(i=1;i<=12;i++) { printf(" %s(%d) ",month_str[i-1],i); printf("0 1 2 3 4 5 6 "); printf("S M T W T F S "); temp=DaySearch(year,i,1); for(j=1;j<=month_day(year,i)+temp;j++) { if(j-temp<=0) printf(" "); else if(j-temp<10) printf("%d ",j-temp); else printf("%d ",j-temp); if(j%7==0) printf(" "); } } return 0; } int main() { int option,da; char ch; int year,month,day; printf("Copyright @ 2005 TianQian All rights reserved!:):):)"); printf(" Welcome to use the WanNianLi system! "); while(1) { printf(" Please select the service you need: "); printf(" 1 Search what day the day is"); printf(" 2 Search whether the year is leap year or not"); printf(" 3 Print the calander of the whole year"); printf(" 4 Exit "); scanf("%d",&option); switch(option) { case 1: while(1) { printf(" Please input the year,month and day(XXXX,XX,XX):"); scanf("%d,%d,%d,%c",&year,&month,&day); da=DaySearch(year,month,day); printf(" %d-%d-%d is %s,do you want to continue?(Y/N)",year,month,day,week[da]); fflush(stdin); scanf("%c",&ch); if(ch=="N"||ch=="n") break; } break; case 2: while(1) { printf(" Please input the year which needs searched?(XXXX)"); scanf("%d",&year); if(IsLeapYear(year)) printf(" %d is Leap year,do you want to continue?(Y/N)",year); else printf(" %d is not Leap year,do you want to continue(Y/N)?",year); fflush(stdin); scanf("%c",&ch); if(ch=="N"||ch=="n") break; } break; case 3: while(1) { printf(" Please input the year which needs printed(XXXX)"); scanf("%d",&year); PrintAllYear(year); printf(" Do you want to continue to print(Y/N)?"); fflush(stdin); scanf("%c",&ch); if(ch=="N"||ch=="n") break; } break; case 4: fflush(stdin); printf("Are you sure?(Y/N)"); scanf("%c",&ch); if(ch=="Y"||ch=="y") exit(0); break; default: printf(" Error:Sorry,there is no this service now! "); break; } } return 0; }
2023-07-07 20:53:481

c语言 求数列中最大值和最小值得差

先排序,再求差
2023-07-07 20:53:585

c语言中函数返回值是指向一维数组的指针的函数怎么写?

typedef double (*point) [2]; point read(int n); 这样如何?
2023-07-07 20:54:163

以下叙述中正确的是a一个c源程序可由一个或多个函数组成b在c程序中注释说明只

以下叙述不正确的是()x0dA:一个C程序可由一个或多个main函数组成x0dB:一个C源程序必须包含一个main函数x0dC:C程序的基本组成单位是函数x0dD:在C程序中,注释说明只能位于一条语句的后面5
2023-07-07 20:54:251

用C语言制作万年历

要DOS下的图形界面的???C++/C#可以不?C太麻烦了 懒得写
2023-07-07 20:54:333

java怎么添加main方法?

public static void main(string[] args){}
2023-07-07 20:54:523

C语言编程 求1 -3 5 -7 9 ....前20项和

#include <stdio.h>#include <stdlib.h>int main(){ int n,sum,i; sum=0; for(i=0; i<20; i++) { n=1+i*2; if(i%2== 1) n=-n; sum+=n; } printf("result:%d",sum); return 0;}
2023-07-07 20:55:023

单片机DA转换产生三角波的c语言程序

你好!你选的那个DA芯片?,是做实物还是仿真就行?
2023-07-07 20:55:111

c语言程序问题

input函数中,需要改为char a[10][80];int i;
2023-07-07 20:55:214

C程序:输入若干字符,分别统计数字字符的个数、英文字母的个数,当输入换行符时输出统计结果,运行结束。

输入用gets,然后分别判断各字符在"0"-"9"之间,还是在"a"-"z"或"A"-"Z"之间
2023-07-07 20:55:302

老师出的turbo C语言设计题目。题目如下,跪求大神帮我打下源代码。参考。

现在不动手,将来想做这一行,还是要动手,自己动动手吧,也不难。
2023-07-07 20:55:361

C语言a,b,c三者间比较大小,程序

写一个程序即可。程序详情:#include "stdio.h"main(){int a,b,c;scanf("%d%d%d",&a,&b,&c);if(a>b&&a>c){if(b>c) printf("%d,%d,%d",a,b,c);else printf("%d,%d,%d",a,c,b);}if(b>c&&b>a){if(a>c) printf("%d,%d,%d",b,a,c);else printf("%d,%d,%d",b,c,a);}if(c>a&&c>b){if(a>b) printf("%d,%d,%d",c,a,b);else printf("%d,%d,%d",c,b,a);}getchar();}
2023-07-07 20:55:472

C语言中一个子函数怎么调用另一个子函数的运算?

#include<stdio.h>void fun2(char a1,char a2,char *a3,int b1,int b2,int *b3,float c1,float c2,float *c3){*a3=a1+a2;*b3=b1+b2;*c3=c1+c2;}void fun1(void){char a1=1,a2=2,a3;int b1=100,b2=300,b3;float c1=5.1,c2=6.8,c3;fun2(a1,a2,&a3,b1,b2,&b3,c1,c2,&c3);printf("a3=%d b3=%d c3=%f ",a3,b3,c3);}int main(){fun1();return 0;}
2023-07-07 20:56:181

C语言题目输入一行字符,分别统计出其中英文字母,空格,数字和其他字符的个数。

#include<stdio.h>int main(){char c;int letters=0,space=0,digit=0,other=0;printf("请输入一段字符 ");while((c=getchar())!=" "){if(c>="a"&&c<="z"||c>="A"&&c<="Z")letters++;else if(c==" ")space++;else if(c>="0"&&c<="9")digit++;elseother++;}printf("字母数:%d 空格数:%d 数字数:%d 其他字符数:%d ",letters,space,digit,other);return 0;}如果没有问题请采纳 谢谢
2023-07-07 20:56:3210

请VB.net高手帮忙看一下这个错误 Fill 参数太多

简单的看了下,你代码写的也太不规范了吧?中西结合啊,你以为中西结合代码就很牛B吗?还是全英文吧。Fill方法有11个重载版本的,但是也不是很复杂,因为我们用的时候也就那么一两个。Fill(DataSet)和Fill(dataset ,tablename)。例如Da.Fill(objDataSet),或者Da.Fill(objDataSet,"Users")。我经常用第二种。你代码中的PasswordTextBox.Text是怎么回事?恕我眼拙!
2023-07-07 20:57:192

mcs 51系列单片机

你这是考试题,还是自己看书吧,书上写的很清楚…
2023-07-07 20:57:491

关于c语言中的类型转换,谢谢了啊!!!

显然是对的嘛!!!
2023-07-07 20:57:572

c++中怎样用枚举类型数据作为二维数组的元素?

#include <stdio.h>enum something{ aa,bb,cc,dd,ee,ff,gg} ;void main(){enum something x[2][3]; int i,j;x[0][0]=dd;x[0][1]=ee;x[0][2]=ff;x[1][0]=aa;x[1][1]=bb;x[1][2]=cc;for (j=0;j<2;j++){for (i=0;i<3;i++) printf("%d ",x[j][i]);printf(" ");}}-------------------------------C++ 头文件换#include<iostream>using namespace std;输出用for (j=0;j<2;j++){for (i=0;i<3;i++) cout << x[j][i] << " ";cout << endl;}
2023-07-07 20:58:114

C语言程序设计题:模拟时钟转动的程序

/*开发环境:turboc2.0模拟时钟转动程序代码*/#include"graphics.h"#include"math.h"#include"dos.h"#definepi3.1415926#defineX(a,b,c)x=a*cos(b*c*pi/180-pi/2)+300#defineY(a,b,c)y=a*sin(b*c*pi/180-pi/2)+240#defined(a,b,c)X(a,b,c);Y(a,b,c);line(300,240,x,y)voidinit()/*划时钟边框函数*/{inti,l,x1,x2,y1,y2;setbkcolor(1);circle(300,240,200);circle(300,240,205);circle(300,240,5);for(i=0;i<60;i++)/*划钟点上的短线*/{if(i%5==0)l=15;elsel=5;x1=200*sin(i*6*pi/180)+300;y1=200*cos(i*6*pi/180)+240;x2=(200-l)*sin(i*6*pi/180)+300;y2=(200-l)*cos(i*6*pi/180)+240;line(x1,y1,x2,y2);}}main(){intx,y,i,k=1;intgdriver=9,gmode=2;unsignedcharh,m,s;into,p,q;floatn;structtimet[1];structdated[1];initgraph(&gdriver,&gmode,"c:\tc");initgraph(&gdriver,&gmode,"c:\tc");for(i=0;i<=6;i++){settextstyle(TRIPLEX_FONT,HORIZ_DIR,i);/*控制输出字符的字体,方向,大小*/cleardevice();settextjustify(1,1);/*在指定坐标上输出字符串*/outtextxy(300,80,"12");outtextxy(300,390,"6");outtextxy(140,230,"9");outtextxy(460,230,"3");outtextxy(380,100,"1");outtextxy(220,100,"11");outtextxy(430,160,"2");outtextxy(430,310,"4");outtextxy(380,370,"5");outtextxy(220,370,"7");outtextxy(160,160,"10");outtextxy(160,310,"8");}init();setwritemode(1);/*设置画线的输出模式*/if(k!=0){getdate(d);/*获得系统日期函数*/o=d[0].da_year;p=d[0].da_mon;q=d[0].da_day;gettime(t);/*获得系统时间函数*/h=t[0].ti_hour;m=t[0].ti_min;s=t[0].ti_sec;}setcolor(7);/*设置时针颜色*/n=(float)h+(float)m/60;d(150,n,30);/*画出时针*/setcolor(14);/*设置分针颜色*/d(170,m,6);/*画出分针*/setcolor(4);/*设置秒针颜色*/d(190,s,6);/*画出秒针*/while(!kbhit())/*控制程序按下任意键退出*/{while(t[0].ti_sec==s)gettime(t);gotoxy(44,18);/*使光标移动到指定坐标*/printf("");/*退格,使表示时间的字符串不断变化*/sound(400);/*按给定的频率打开PC扬声器*/delay(70);/*中断程序的执行,时间为70毫秒*/sound(200);delay(30);nosound();/*按给定的频率关闭PC扬声器*/setcolor(4);d(190,s,6);s=t[0].ti_sec;d(190,s,6);if(t[0].ti_min!=m){setcolor(14);d(170,m,6);m=t[0].ti_min;d(170,m,6);}if(t[0].ti_hour!=h){setcolor(7);d(150,h,30);h=t[0].ti_hour;d(150,h,30);sound(1000);delay(240);nosound();delay(140);sound(2000);delay(240);nosound();}if(s<10)/*用字符的形式输出时间*/{if(m<10)printf("%u:0%u:0%u",h,m,s);elseprintf("%u:%u:0%u",h,m,s);}else{if(m<10)printf("%u:0%u:%u",h,m,s);elseprintf("%u:%u:%u",h,m,s);}gotoxy(34,19);/*在指定坐标上输出日期*/printf("%d年%d月%d日",o,p,q);printf("");}getch();closegraph();}
2023-07-07 20:58:213