因式分解x2y2+2xy+2x2y+2xy2

eyong5232022-10-04 11:39:541条回答

因式分解x2y2+2xy+2x2y+2xy2
x²y²+2xy+2x²y+2xy²=140 求xy

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x²y²+2xy+2x²y+2xy²
=x²y²+2xy(x+y)+2xy
=x²y²+{2xy[(x+y)+1]}
=x²y²+[2xy(x+y+1)]
1年前

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