f(x)=ax+1-x2,g(x)=3ln(x),设h(x)=f(x)-g(x)

0=a2x2+b2(1-2x+x2)+2abx-2abx2
a2x+b2-b2x>=a2x2+b2-2b2x+b2x2+2abx-2abx2
(a2-b2)x+b2>=(a2+b2-2ab)x2-(2b2-2ab)x+b2
(a2-b2)x+(2b2-2ab)x+b2>=(a-b)2x2+b2
(a-b)2x+b2>=(a-b)2x2+b2
因为a不等于b,则有：
x2-x

1.若f（x)=x^2-ax+10
a>2或a

f(x)=(1+1/tanax)sin²ax-2sin(ax+π/4)sin(ax-π/4),
化简得,f(x)=sin²ax+cosax*sinax-cos(2ax)-cos(π/2)
f(x)=sin²ax+cosax*sinax-cos(2ax)
f(x)=sin²ax+cosax*sinax-cos²ax+sin²ax
f(x)=2sin²ax+cosax*sinax-cos²ax
f(x)=1-cos2ax+(sin2ax)/2-(cos2ax)/2-1/2
其周期为2π/2a,即π/a,
而此处相邻切点距离π/2,因此a=2

将f(x)对x求导,
df(x)/dx=4sinax*cosax-sin²ax+cos²ax+2cosax*sinax
df(x)/dx=-sin²ax+cos²ax-2cosax*sinax=cos2ax-sin2ax
与y=m相切,必定df(x)/dx=0
即cos2ax-sin2ax=0
x=π/16+nπ/4,
将x=π/16,代入f(x)中,得f(x)=1-(2^0.5)/2+(2^0.5)/4-(2^0.5)/4+1/2=1/2-(2^0.5)/2
将x=π/16+π/4代入f(x)中,得f(x)=1+(2^0.5)/2-(2^0.5)/4+(2^0.5)/4+1/2=1/2+(2^0.5)/2
因此m=1/2-(2^0.5)/2或者1/2+(2^0.5)/2


A为其对称中心,则A点的横坐标为x0=π/16+nπ/4,n=0.5
即x0=3π/16,将x0代入得到的y0,（x0,y0）即为A点坐标

A={X|x2-x-6<0},x2-x-6<0 (x+2)(x-3)<0 -20 4-2a+1>0 9+3a+1>0 解不等式组得,a的范围为:-10/3

1年前

4

不知道你想问什么,光给一个函数.
求导的话：
f'(x)=2e^(2x+1)-a

ln(ax+1-2a)>2ln(x-1)
ln(ax+1-2a)>ln(x-1)²
即ax+1-2a>(x-1)²
得x²-(2+a)x+2a