(2y-1)/3-(10y+1)/6=(2y+1),5x/12=(2x-1)/4-1 1/3[3y-(10-7y)/2]

vanyar2022-10-04 11:39:541条回答

(2y-1)/3-(10y+1)/6=(2y+1),5x/12=(2x-1)/4-1 1/3[3y-(10-7y)/2]-1/2[2y-(2y+2)/3]=y/2-1

已提交，审核后显示！提交回复

踏风追梦共回答了19个问题 | 采纳率78.9%: (2y-1)/3-(10y+1)/6=(2y+1)
2(2y-1)-10-1=12y+6
-8y=19
y=-19/8
5x/12=(2x-1)/4-1
5x=4(2x-1)
-3x=-4
x=4/3
1/3[3y-(10-7y)/2]-1/2[2y-(2y+2)/3]=y/2-1
y-(10-7y)/6-y+(2y+2)/6=y
-(10-7y)+2y+2=6y
3y=8
y=8/3; 1年前