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分式计算题及答案10道

2023-05-20 02:15:50
TAG: 分式
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1、9/7 - ( 2/7 – 10/21 )

2、5/2 -( 3/2 + 4/5 )

3、7/8 + ( 1/8 + 1/9 )

4、6/2 -( 3/2 + 4/5 )

5、8 + ( 1/8 + 1/9 )

6、4/7 - ( 2/7 – 10/21 )

7、2/9+1/2-4/5+3/8

8、1/2+1/4+4/5-1/8

9、3-5/4 + 1/4

10、3/14 - 2/3 + 1/6

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2 a+1-a+3 a2-4a-5÷a2-9 a2-3a-10.解 原式=[x+2 x(x-2)-x-1(x-2)2]•x 4-x (括号内分式的分母中的多项式式分解因式.分式的除法法则) =[(x+2)(x-2)x(x-2)2-x(x-1)x(x-2)2]•x4-x(异分母的分式减法的法则) =x2-4-x2+x x(x-2)2•x4-x (整式运算) =x-4x(x-2)2•x4-x (合并同类项) =x-4 x(x-2)2•(-xx-4) (分式的符号法则) =-1(x-2)2. (分式的乘法法则)计算x+y x2-xy +(x2-y2 x)2•(1 y-x)3.解 原式=x+y x(x-y)+(x+y)2(x-y)2x2•1(y-x)3 =x+y x(x-y)-(x+y)2 x2(x-y) =x2+xy-x2-2xy-y2 x2(x-y) =-xy-y2 x2(x-y)=-xy+y2 x2(x-y).x-y+4xy x-y)(x+y-4xyx+y)答案x2-y2[1 (a+b)2-1(a-b)2]÷(1a+b-1a-b)答案2a (a+b)(a-b); x x-y• y2 x+y-x4y x4-y4÷x2 x2+y2答案-xy x+y3x-2 x2-x-2+(1-1x+1)÷(1+1x-1)答案x2 (x+1)(x-2);(2x x+1+2 x-1+4x x2-1)×(2x x+1+2 x-1-4x x2-1).答案4(2m^2-4m)/(2-m)(m-1)-(1+m)/(1-m^2)=2m(m-2)/(2-m)(m-1)-(1+m)/(1-m)(1+m)=-2m/(m-1)-1/(1-m)=(2m-1)/(1-m)(-1)-a^2)/(a-1)-a=(1-a-a^2-a^2+a)/(a-1)=-(2a^2-1)/(a-1)(5/x-1)-(3/x+2)+(3/x+3)-(5/x-2)原式=[5(x+2)-3(x-1)]/(x-1)(x+2)-[5(x+3)-3(x-2)]/(x-2)(x+3)=(2x+13)/(x²+x-2)-(2x+21)/(x²+x-6)=[(2x+13)(x²+x-6)-(2x+21)(x²+x-2)]/(x²+x-6)(x²+x-2)=(2x³+16x²+x-78-2x³-23x²-17x+42)/(x²+x-6)(x²+x-2)=(-7x²-16x-36)/(x^4+2x³-7x²-8x+12)1/6x-4y - 1/6x+4y +3x/4y^2-9x^2 =[6x+4y-(6x-4y)-12x]/(36x^2-16y^2) =(8y-12x)/(36x^2-16y^2) =4(2y-3x)/[4(3x+2y)(3x-2y)] =-1/(3x+2y)(2)1/1-x +1/1+x +2/1+x^2 +4/1+x^4 =2/(1-x^2)+2/(1+x^2)+4/(1+x^4) =4/(1-x^4)+4/(1+x^4) =8/(1-x^8)1.(2x分之3) + 2 = 02.(x-1分之x) + (x+1分之2) =13.(x+1分之1) - (x²+3x+2分之x²)=-1 3/2x=-23=-4xx=-3/4x/(x-1)+2/(x+1)=1x(x+1)+2(x-1)=(x-1)(x+1)x^2+x+2x-2=x^2-13x=1x=1/31/(x+1)-x^2/(x^2+3x+2)=-11/(x+1)-x^2/(x+1)(x+2)=-1(x+2)/(x+1)(x+2)-x^2(x+1)(x+2)=-1x+2-x^2=-(x+1)(x+2)x^2-x-2=x^2+3x+24x=-4x=-1拓展:原题=1-1/2+1/2-1/3....+1/99-1/100 =1-1/100 (2):根据(1)得: 1-1/2+1/2-1/3+.....+1/N-1/(N+1) =1-1/(N+1) 3.(1)1/1*2+1/2*3+1/3*4+...+1/99*100=(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/99-1/100)=1-1/100=99/100 (2)1/1*2+1/2*3+1/3*4+...+1/n(n+1)==(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+[1/n-1/(n+1)]=1-1/(n+1)=n/(n+1)我尽力了 不够我也没办法了。。
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初二分式运算计算题及答案20道

2 a+1-a+3 a2-4a-5÷a2-9 a2-3a-10. 解 原式=[x+2 x(x-2)-x-1(x-2)2]x 4-x (括号内分式的分母中的多项式式分解因式.分式的除法法则) =[(x+2)(x-2)x(x-2)2-x(x-1)x(x-2)2]x4-x(异分母的分式减法的法则) =x2-4-x2+x x(x-2)2x4-x (整式运算) =x-4x(x-2)2x4-x (合并同类项) =x-4 x(x-2)2(-xx-4) (分式的符号法则) =-1(x-2)2. (分式的乘法法则) 计算x+y x2-xy +(x2-y2 x)2(1 y-x)3. 解 原式=x+y x(x-y)+(x+y)2(x-y)2x21(y-x)3 =x+y x(x-y)-(x+y)2 x2(x-y) =x2+xy-x2-2xy-y2 x2(x-y) =-xy-y2 x2(x-y)=-xy+y2 x2(x-y). x-y+4xy x-y)(x+y-4xyx+y) 答案x2-y2 [1 (a+b)2-1(a-b)2]÷(1a+b-1a-b) 答案2a (a+b)(a-b); x x-y y2 x+y-x4y x4-y4÷x2 x2+y2 答案-xy x+y 3x-2 x2-x-2+(1-1x+1)÷(1+1x-1) 答案x2 (x+1)(x-2); (2x x+1+2 x-1+4x x2-1)×(2x x+1+2 x-1-4x x2-1). 答案4 (2m^2-4m)/(2-m)(m-1)-(1+m)/(1-m^2) =2m(m-2)/(2-m)(m-1)-(1+m)/(1-m)(1+m) =-2m/(m-1)-1/(1-m) =(2m-1)/(1-m) (-1)-a^2)/(a-1)-a =(1-a-a^2-a^2+a)/(a-1) =-(2a^2-1)/(a-1) (5/x-1)-(3/x+2)+(3/x+3)-(5/x-2) 原式=[5(x+2)-3(x-1)]/(x-1)(x+2)-[5(x+3)-3(x-2)]/(x-2)(x+3) =(2x+13)/(x+x-2)-(2x+21)/(x+x-6) =[(2x+13)(x+x-6)-(2x+21)(x+x-2)]/(x+x-6)(x+x-2) =(2x+16x+x-78-2x-23x-17x+42)/(x+x-6)(x+x-2) =(-7x-16x-36)/(x^4+2x-7x-8x+12) 就这些了。 追问 不够,再来一些就给你分 回答 (1)1/6x-4y - 1/6x+4y +3x/4y^2-9x^2 =[6x+4y-(6x-4y)-12x]/(36x^2-16y^2) =(8y-12x)/(36x^2-16y^2) =4(2y-3x)/[4(3x+2y)(3x-2y)] =-1/(3x+2y) (2)1/1-x +1/1+x +2/1+x^2 +4/1+x^4 =2/(1-x^2)+2/(1+x^2)+4/(1+x^4) =4/(1-x^4)+4/(1+x^4) =8/(1-x^8) 1.(2x分之3) + 2 = 0 2.(x-1分之x) + (x+1分之2) =1 3.(x+1分之1) - (x+3x+2分之x)=-1 3/2x=-2 3=-4x x=-3/4 x/(x-1)+2/(x+1)=1 x(x+1)+2(x-1)=(x-1)(x+1) x^2+x+2x-2=x^2-1 3x=1 x=1/3 1/(x+1)-x^2/(x^2+3x+2)=-1 1/(x+1)-x^2/(x+1)(x+2)=-1 (x+2)/(x+1)(x+2)-x^2(x+1)(x+2)=-1 x+2-x^2=-(x+1)(x+2) x^2-x-2=x^2+3x+2 4x=-4 x=-1 拓展:原题=1-1/2+1/2-1/3....+1/99-1/100 =1-1/100 (2):根据(1)得: 1-1/2+1/2-1/3+.....+1/N-1/(N+1) =1-1/(N+1) 3.(1)1/1*2+1/2*3+1/3*4+...+1/99*100=(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/99-1/100)=1-1/100=99/100 (2)1/1*2+1/2*3+1/3*4+...+1/n(n+1)==(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+[1/n-1/(n+1)]=1-1/(n+1)=n/(n+1)
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2023-01-13 22:53:141

分式计算题及详细答案过程30道

现出的:1.ax+by+ay+bx2.x^3+13.x^2+x^34.x^2+x^3-25.x^2-6x+86.x^2-12x+357.(x^3-1)+(x-1)(6x+11)8.x^4-19.x^4+410.b^2+ab+ac+bc11.x^3+y^3+z^3-3xyz12.x^6+8x^3+913.x^2-100x+9914.x^2-x-y^2-y15.7x^2-19x-616.8x^2-6x-917.x+1)(x+2)-1218.x^2+(p+q)x+pq19.3x^3-6x^2+320.a^2(x-2a)^2-a(x-2a)^221.25m^2-10mn+n^222.x^2-3x-2823.y^4+2y^3-3y^224.(x-1)^2*(3x-2)+(2-3x)25.(x-2)^2-x+226.x^2-12x-2827.12a^2*b(x-y)-4ab(y-x)28.a^2+5a+629.x^11-2x^10+x^930.x^2+x31.x^3+x32.x^4+x33.100x^2+30xy+2y^234.6y^2-16y+835.6-7a-5a^236.3x^2-17x+1037.6a^2-11ab+3b^238.2m^3+3m^2-5m39.(x+y)^2-2(x+y)-340.a^2-b^2+2ab-c^241.m^2+2mn+n^2-142.x^2-4y^2+4yz-z^243.9x^2-4y^2-z^2+4yz44.-25+a^2+9b^2-6ab45.2x^2-100x-10246.x^2*y^2-7xy+1047.x^2-x-248.-x^2*y+6xy-8y49.x^2-9y^2-x+3y50.x^2-7x-8出不动了。。。难度不随题号变化,解题方法不随题号变化,老少皆宜,童叟无欺。答案:1.(a+b)(x+y)2.(x+1)(x^2-x+1)3.x^2*(x+1)4.(x-1)(x^2-2x+2)5.(x-2)(x-4)6.(x-5)(x-7)7.(x-1)(x+3)(x+4)8.(x^2+1)(x-1)(x+1)9.(x^2-2x+2)(x^2+2x+x)10.(b+c)(b+a)11.(x+y+z)(x^2+y^2+z^2-xy-yz-xz)12.(x+1)(x^2-x+1)(x+2)(x^2-2x+4)13.(x-99)(x-1)14.(x+y)(x-y-1)15.(7x+2)(x-3)16.(2x-3)(4x+3)17.(x+5)(x-2)18.(x+p)(x+q)19.(x-1)(x^2-x-1)20.a(a-1)(x-2a)^221.(5m-n)^222.(x-7)(x+4)23.y^2(y-1)(y+3)24.x(x-2)(3x-2)25.(x-2)(x-3)26.(x-14)(x+2)27.4ab(3a+1)(x-y)28.(a+2)(a+3)29.x^9*(x-1)^230.x(1+x)31.x(1+x^2)32.x(1+x)(1-x+x^2)33.2(5x+y)(10x+y)34.2(3y-2)(y-2)35.(3-5a)(a+2)36.(3x-2)(x-5)37.(2a-3b)(3a-b)38.m(m-1)(2m+5)39.(x+y-3)(x+y+1)40.(a+b-c)(a+b+c)41.(m+n+1)(m+n-1)42.(x+2y-z)(x-2y+z)43.(3x+2y-z)(3x-2y+z)44.(a-3b-5)(a-3b+5)45.2(x-51)(x+1)46.(xy-5)(xy-2)47.(x-2)(x+1)48.-y(x-2)(x-4)49.(x-y)(x+3y-1)50.(x-8)(x+1)
2023-01-13 22:53:171

两个分式计算题

第一题就是两边先同时乘x-2,然后在同时乘x,这样分式就被化简了。第二题也是同理,同时先乘x,在同时乘x+10,就可以了。
2023-01-13 22:53:201

分式方程的计算题!!!

x-2/2-1=x²-4/1两边乘(x+2)(x-2)2(x+2)-(x+2)(x-2)=1x²-2x-7=0x=1-2√2,x=1+2√21-3x/1-2/3=3x-1/2两边乘2(3x-1)-2-3(3x-1)=29x+1=0x=-1/9若分式方程x/1+x-1/2=x²-x/k有解,求k的取值范围两边乘x(x-1)(x-1)+2x=k3x=k+1x=(k+1)/3有解则不是增根所以分母不等于0x≠0,x≠1(k+1)/3≠0,(k+1)/3≠1所以k≠-1且k≠2当m的值满足什么条件时,关于x的方程x/3+x-1/6=x(x-1)/x+m不会产生曾根两边乘x(x-1)3x-3+6x=x+mx=(m+3)/8没有增根则分母不等于0x≠0,x≠1(m+3)/8≠0,(m+3)/8≠1所以m≠-3且m≠4
2023-01-13 22:53:241

初二的几道分式计算题

第一题:设所求为X,则1500/x是规定时间,1600/2x是提高后时间1500/x-1500/2x=5第二题:原式为(2-x/x-3)-(1/x-3)=1移项通分2-x-1=x-3x=2第三题:等式两侧同乘(2x+5)(5x-2)2x(5x-2)+5(2x+5)=(2x+5)(5x-2)打开括号合并同类项得15x=35x=7/3第四题:原式为a-a^2-((a-1)^2/(a-1))=a-a^2-a+1=1-a^2
2023-01-13 22:53:276

跪求初二下数学分式计算题(80道)

初二数学单元练习题(分式)一、选择题:1、分式的值不可能为0的是 (B) A、 B、 C、 D、 2、若分式的值为0时, ,则下列分式符合的是( D ) A、 B、 C、 D、 3、将分式 中的 都扩大15倍,则分式的值( ) A、扩大15倍 B、缩小为原来的 C、是原数的 D、不变4、分式: 中,最简分式有( ) A、1个 B、2个 C、3个 D、4个5、下列各式正确的是( )A、 B、 C、 D、 6、若分式 与 的值互为倒数,则 等于( )A、 B、 C、 D、 7、对于分式 ,当 时,下列正确的是( )A、分式无意义 B、分式的值为1 C、分式的值为0 D、分式的值为 8、若 ,用 表示 的式子是( )A、 B、 C、 D、 9、某食堂有煤 吨,原计划每天烧 吨,现在每天节约 吨,则可比原计划多烧的天数是( )A、 B、 C、 D、 10、若 ,则 等于( )A、 B、 C、 D、 二、填空题:11、下列式子中:① ;② ;③ ;④ ;⑤ 。其中是分式的有 。(填序号) 12、不改变分式的值,使分式的分子、分母都不含负号, ; 13、若 无意义,那么 与 的关系是 。14、 = ;
2023-01-13 22:53:361

大神快进坐等!!数学分式计算题: (x^2-4y^2)/x^2+2xy+y^2÷x+2y/2x^2+2xy.

原式=(x-2y)(x+2y)/(x+y)²÷2x(x+y)/x+2y =2x(x-2y)/(x+y)标准答案,望采纳,谢谢
2023-01-13 22:53:403

分数解方程计算题

………………
2023-01-13 22:53:434

一道数学分式乘除题~计算题!

这式子写的也太乱了,完全看不懂
2023-01-13 22:53:463

分式的加减法,计算题。

2a+1-a+3a2-4a-5÷a2-9a2-3a-10.解原式=[x+2x(x-2)-x-1(x-2)2]??x4-x(括号内分式的分母中的多项式式分解因式.分式的除法法则)=[(x+2)(x-2)x(x-2)2-x(x-1)x(x-2)2]??x4-x(异分母的分式减法的法则)=x2-4-x2+xx(x-2)2??x4-x(整式运算)=x-4x(x-2)2??x4-x(合并同类项)=x-4x(x-2)2??(-xx-4)(分式的符号法则)=-1(x-2)2.(分式的乘法法则)计算x+yx2-xy+(x2-y2x)2??(1y-x)3.解原式=x+yx(x-y)+(x+y)2(x-y)2x2??1(y-x)3=x+yx(x-y)-(x+y)2x2(x-y)=x2+xy-x2-2xy-y2x2(x-y)=-xy-y2x2(x-y)=-xy+y2x2(x-y).x-y+4xyx-y)(x+y-4xyx+y)答案x2-y2[1(a+b)2-1(a-b)2]÷(1a+b-1a-b)答案2a(a+b)(a-b);xx-y??y2x+y-x4yx4-y4÷x2x2+y2答案-xyx+y3x-2x2-x-2+(1-1x+1)÷(1+1x-1)答案x2(x+1)(x-2);(2xx+1+2x-1+4xx2-1)×(2xx+1+2x-1-4xx2-1).答案4(2m^2-4m)/(2-m)(m-1)-(1+m)/(1-m^2)=2m(m-2)/(2-m)(m-1)-(1+m)/(1-m)(1+m)=-2m/(m-1)-1/(1-m)=(2m-1)/(1-m)(-1)-a^2)/(a-1)-a=(1-a-a^2-a^2+a)/(a-1)=-(2a^2-1)/(a-1)(5/x-1)-(3/x+2)+(3/x+3)-(5/x-2)原式=[5(x+2)-3(x-1)]/(x-1)(x+2)-[5(x+3)-3(x-2)]/(x-2)(x+3)=(2x+13)/(x??+x-2)-(2x+21)/(x??+x-6)=[(2x+13)(x??+x-6)-(2x+21)(x??+x-2)]/(x??+x-6)(x??+x-2)=(2x??+16x??+x-78-2x??-23x??-17x+42)/(x??+x-6)(x??+x-2)=(-7x??-16x-36)/(x^4+2x??-7x??-8x+12)1/6x-4y-1/6x+4y+3x/4y^2-9x^2=[6x+4y-(6x-4y)-12x]/(36x^2-16y^2)=(8y-12x)/(36x^2-16y^2)=4(2y-3x)/[4(3x+2y)(3x-2y)]=-1/(3x+2y)(2)1/1-x+1/1+x+2/1+x^2+4/1+x^4=2/(1-x^2)+2/(1+x^2)+4/(1+x^4)=4/(1-x^4)+4/(1+x^4)=8/(1-x^8)1.(2x分之3)+2=02.(x-1分之x)+(x+1分之2)=13.(x+1分之1)-(x??+3x+2分之x??)=-13/2x=-23=-4xx=-3/4x/(x-1)+2/(x+1)=1x(x+1)+2(x-1)=(x-1)(x+1)x^2+x+2x-2=x^2-13x=1x=1/31/(x+1)-x^2/(x^2+3x+2)=-11/(x+1)-x^2/(x+1)(x+2)=-1(x+2)/(x+1)(x+2)-x^2(x+1)(x+2)=-1x+2-x^2=-(x+1)(x+2)x^2-x-2=x^2+3x+24x=-4x=-1拓展:原题=1-1/2+1/2-1/3....+1/99-1/100=1-1/100(2):根据(1)得:1-1/2+1/2-1/3+.....+1/n-1/(n+1)=1-1/(n+1)3.(1)1/1*2+1/2*3+1/3*4+...+1/99*100=(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/99-1/100)=1-1/100=99/100(2)1/1*2+1/2*3+1/3*4+...+1/n(n+1)==(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+[1/n-1/(n+1)]=1-1/(n+1)=n/(n+1)
2023-01-13 22:53:541

初二的分式计算题:

1/[a(a+1)]+1/[(a+1)(a+2)+1/[(a+2)(a+3)]+……+1/[(a+2004)(a+2005)]     =1/a-1/(a+1)+1/(a+1)-1/(a+2)+1/(a+2)-1/(a+3)+……+1/(a+2004)-1/(a+2005)     =1/a-1/(a+2005)     =2005/[a(a+2005)] 2.若分式 (3x-1)/[(x-1)(x-2)]=A/(x-1)+B/(x-2) ,那么,    A/(x-1)+B/(x-2)  =[A(x-2)+B(x-1)]/[(x-1)(x-2)]  =[x(A+B)-2A-B]/[(x-1)(x-2)]则:A+B=3 …………(1)       2A+B=1…………(2)    (2)-(1)得:A=-2        代入(1)得: B=5 .即:A=-2     B=5  .                   
2023-01-13 22:53:571

初中数学分式计算题

题呢???要答什么??
2023-01-13 22:54:017

初二分式计算题

是要两道题还是……?
2023-01-13 22:54:103

分式方程计算题100道

2x+17=35 3x-64=11 12+8x=52 0.8x-4.2=2.2 2x+5=10 3x-15=75 4x+4o=320 3x+77=122 5x-1.6=0.6 6x-4=20 10x-0.6=2.4 500-12x=140 1) 66x+17y=3967 25x+y=1200 答案:x=48 y=47 (2) 18x+23y=2303 74x-y=1998 答案:x=2...
2023-01-13 22:54:241

分式方程计算题来20道

1..若A/(x-5)+B/(x-2)=(5x-4)/(x^2-3x-10),试求A、B的值改过的答:你的问题是不是有问题?因为这一类题目应该是这样子的吧A/(x-5)+B/(x-2)=(5x-4)/(x^2-7x+10)两边相乘(X-5)(X-2)A(X-2)+B(X-5)=(5X-4)(X-5)(X-2)/(X^2-7X+10)把相同的种类归在一起,变成这样子。(A+B)X-(2A+5B)=(5X-4)(X-5)(X-2)/(X-5)(X-2)(A+B)X-(2A+5B)=(5X-4)(A+B)X=5X所以A+B=5,然后改A=5-B-2A-5B=-4-2(5-B)-5B=-4-10+2B-5B=-4-3B=6B=-2A=5-(-2)A=7这一类题目就是这么做,希望你满意。2.若1/R=1/R1+1/R2,且R1+R2不等於0,求R答:1/R=1/r1+1/r2=(r1+r2)/r1r2R=r1r2/(r1+r2)3.巳知a^2-6a+9与│b-1│互为相反数,则式子(a/b-b/a)/(a+b)的值为?答:因为a^2-6a+9与|b-1|互为相反数则a^-6a+9+|b-1|=0(a-3)^2+|b-1|=0则a-3=0a=3b-1=0b=1(a/b-b/a)÷(a+b)=2/34.巳知1/x-1/y,则分式(2x+3xy-2y)/(x-2xy-y)的值为?这个问题有点怪,给个比方已知1/x-1/y=3(这才能找到答案吧)所以把问题改点已知1/x-1/y=3,则分式(2x+3xy-2y)/(x-2xy-y)的值为?答:1/x-1/y=3(y-x)/xy=3y-x=3xyx-y=-3xy所以(2x+3xy-2y)/(x-2xy-y)=[2(x-y)+3xy]/[(x-y)-2xy]=-3xy/-5xy=3/5
2023-01-13 22:54:411

2017除以2017又2018分之2017简便计算?

2017÷(2017+2017/2018)= 2017÷[2017×(1+1/2018)]= 2017÷2017÷(1+1/2018)= 1÷(1+1/2018)= 1÷2019/2018= 2018/2019
2023-01-13 22:54:462

分式计算题

1.1/x+1/3y=1/6将等式化为:(3y+x)/3xy=1/6得:18y+6x=3xy.则要求的分式可化简为(xy-3xy)/12xy=-2xy/12xy=-1/6
2023-01-13 22:54:492

初中分式计算题,求答案和过程

5. a/x-a +b=1 a/x-a=1-b a=(1-b)*(x-a) a/1-b=x-a x=a/1-b +a
2023-01-13 22:54:543

分式计算题

2AB
2023-01-13 22:55:022

求10道分式方程计算题如题 只要计算题~

1.1/2x=2/x+3; 7.1/(x+2) + 1/(x+7) = 1/(x+3) + 1/(x+6) 2.7/(x^2+x)+1/(x^2-x)=6/(x^2-1) 8.(2-x)/(x-3)+1/(3-x)=1 3.x/(x+1)=2x/(3x+3)+1 9.(X+2)/X=(X+5)/(X+1) 4.2/x-1=4/x^2-1 10.(x+5)/(x+8)=(x+6)/(x+7) 5.5/x^2+x - 1/x^2-x=0 6.5x/(3x-4)=1/(4-3x)-2
2023-01-13 22:55:051

关于分式化简的计算题

x/x^2-1 * x^2+1/x=x^2+1/x^2-1
2023-01-13 22:55:092

分式计算题

(2分之根号3-根号7)^2+根号7-根号3分之根号7+根号3=3/4-√21+7+√7-√21/3+√3=31/4-4√21/3+√7+√3明教为您解答,如若满意,请点击[满意答案];如若您有不满意之处,请指出,我一定改正!希望还您一个正确答复!祝您学业进步!
2023-01-13 22:55:121

分式方程计算题来20道

1..若A/(x-5)+B/(x-2)=(5x-4)/(x^2-3x-10),试求A、B的值改过的答:你的问题是不是有问题?因为这一类题目应该是这样子的吧A/(x-5)+B/(x-2)=(5x-4)/(x^2-7x+10)两边相乘(X-5)(X-2)A(X-2)+B(X-5) = (5X-4)(X-5)(X-2)/ (X^2-7X+10)把相同的种类归在一起,变成这样子。(A+B)X - (2A+5B) = (5X-4)(X-5)(X-2) / (X-5)(X-2) (A+B)X - (2A+5B) = (5X-4)(A+B)X = 5 X所以A+B=5, 然后改A=5-B-2A-5B= -4-2(5-B)-5B=-4-10+2B-5B=-4-3B=6B=-2A=5-(-2)A=7这一类题目就是这么做,希望你满意。2.若1/R=1/R1+1/R2,且R1+R2不等於0,求R答:1/R=1/r1+1/r2=(r1+r2)/r1r2R=r1r2/(r1+r2)3.巳知a^2-6a+9与│b-1│互为相反数,则式子(a/b-b/a)/(a+b)的值为?答:因为a^2-6a+9与|b-1|互为相反数则a^-6a+9+|b-1|=0(a-3)^2+|b-1|=0则a-3=0a=3b-1=0b=1(a/b-b/a)÷(a+b)=2/34.巳知1/x-1/y,则分式(2x+3xy-2y)/(x-2xy-y)的值为?这个问题有点怪,给个比方已知1/x-1/y=3(这才能找到答案吧)所以把问题改点已知1/x-1/y=3,则分式(2x+3xy-2y)/(x-2xy-y)的值为? 答:1/x-1/y=3(y-x)/xy=3y-x=3xyx-y=-3xy所以(2x+3xy-2y)/(x-2xy-y)=[2(x-y)+3xy]/[(x-y)-2xy]=-3xy/-5xy=3/5
2023-01-13 22:55:162

初中分式计算题,求答案和过程

1.02.1(a+2)3.分式两边同时*(X-1)(X+1)得:5(X+1)=3(X-1):移项得:2X=-3-5解得:X=-44.原式可化为:X-1/X-2=X-3/2-X通分得:X-1=3-X解得:X=25.移项得:a/x=a-b缉绩光啃叱救癸寻含默解得:x=(a-b)/a6.原式=((a-b)^2+4ab)/(a-b))*((a+b)^2-4ab)/(a+b))=(a+b)^2/(a-b)*(a-b)^2/(a+b)=(a+b)(a-b)=a^2-b^27.3-38.-6.4*10^69.1/X^2
2023-01-13 22:55:212

分式计算题

题目嘞?
2023-01-13 22:55:252

求初二数学分式计算题

自己慢慢算
2023-01-13 22:55:333

急求!初二分式计算题 谢谢

~~DA_________AN_____________1.当m≠4时,方程mx-n=4x的解是?mx-n=4x所以n=(m-4)·x∵m≠4∴m-4≠0。所以x=n/(m-4)(分母不等于0)。2.若分式ab/a+b(ab均不为0)中的ab都括大到10a和10b,则分式的值扩大到原来的____倍?解:原式=10a`10b/(10a+10b)=100ab/10(a+b)=10ab/(a+b)这个式呢,等于原来的ab/(a+b)乘以10,所以值扩大到了原来的10倍。3.a/b=3,则(a^2+b^2)/ab=?解:a/b=3∴a=3b将a=3b代入那个式子,得原式=(3b)^2+b^2/3b^2=10b^2/3b^2=3/10(0.3)4.已知m/x²y²=(2xy-y²/x²-y²)+(x-y/x+y).则m=?解:m/x²y²=(2xy-y²/x²-y²)+(x-y)²/x²-y²m/x²y²=2xy-y²+(x²+y²-2xy)/x²-y²m/x²y²=x²/x²-y²所以呢,m(x²-y²)=x^4`y²所以呢,当x≠y≠0,且x+y≠0的时候m=x^4`y²/(x²-y²)这个,不知道对不对哈,然后至于六题呢,你好像抄错了,仔细看看哈~~~
2023-01-13 22:55:371

初二数学分式计算题

1/(1-x)+1/(1+x)=2/(1-xx)2/(1-xx)+2/(1+xx)=4/(1-xxxx)1(1-x)+1/(1+x)+2/(1+xx)+4/(1+xxxx)=8/(1-xxxxxxxx)所以上式结果为0
2023-01-13 22:55:413

要分式计算题20道!急~~星期六要!

一1/(a^2-ab-ac+bc)+1/(b^2-ab-bc+ac) 二1-(4x)/(2x+y)-(2x+y)/(2x-y)-(8xy)/(4x^2-y^2)
2023-01-13 22:55:443

分式计算题?

甲:100(a+b)/(100+100) =a+b乙:(100+100)/(100/a+100/b) =2ab/(a+b) a+b-2ab/(a+b)>0所以乙的单价便宜
2023-01-13 22:55:482

急求初二的分式运算计算题50道,应用题不要,只要计算题,要带答案!

2a+1-a+3a2-4a-5÷a2-9a2-3a-10.解原式=[x+2x(x-2)-x-1(x-2)2]•x4-x(括号内分式的分母中的多项式式分解因式.分式的除法法则)=[(x+2)(x-2)x(x-2)2-x(x-1)x(x-2)2]•x4-x(异分母的分式减法的法则)=x2-4-x2+xx(x-2)2•x4-x(整式运算)=x-4x(x-2)2•x4-x(合并同类项)=x-4x(x-2)2•(-xx-4)(分式的符号法则)=-1(x-2)2.(分式的乘法法则)计算x+yx2-xy+(x2-y2x)2•(1y-x)3.解原式=x+yx(x-y)+(x+y)2(x-y)2x2•1(y-x)3=x+yx(x-y)-(x+y)2x2(x-y)=x2+xy-x2-2xy-y2x2(x-y)=-xy-y2x2(x-y)=-xy+y2x2(x-y).x-y+4xyx-y)(x+y-4xyx+y)答案x2-y2[1(a+b)2-1(a-b)2]÷(1a+b-1a-b)答案2a(a+b)(a-b);xx-y•y2x+y-x4yx4-y4÷x2x2+y2答案-xyx+y3x-2x2-x-2+(1-1x+1)÷(1+1x-1)答案x2(x+1)(x-2);(2xx+1+2x-1+4xx2-1)×(2xx+1+2x-1-4xx2-1).答案4(2m^2-4m)/(2-m)(m-1)-(1+m)/(1-m^2)=2m(m-2)/(2-m)(m-1)-(1+m)/(1-m)(1+m)=-2m/(m-1)-1/(1-m)=(2m-1)/(1-m)(-1)-a^2)/(a-1)-a=(1-a-a^2-a^2+a)/(a-1)=-(2a^2-1)/(a-1)(5/x-1)-(3/x+2)+(3/x+3)-(5/x-2)原式=[5(x+2)-3(x-1)]/(x-1)(x+2)-[5(x+3)-3(x-2)]/(x-2)(x+3)=(2x+13)/(x²+x-2)-(2x+21)/(x²+x-6)=[(2x+13)(x²+x-6)-(2x+21)(x²+x-2)]/(x²+x-6)(x²+x-2)=(2x³+16x²+x-78-2x³-23x²-17x+42)/(x²+x-6)(x²+x-2)=(-7x²-16x-36)/(x^4+2x³-7x²-8x+12)就这些了。追问不够,再来一些就给你分回答(1)1/6x-4y-1/6x+4y+3x/4y^2-9x^2=[6x+4y-(6x-4y)-12x]/(36x^2-16y^2)=(8y-12x)/(36x^2-16y^2)=4(2y-3x)/[4(3x+2y)(3x-2y)]=-1/(3x+2y)(2)1/1-x+1/1+x+2/1+x^2+4/1+x^4=2/(1-x^2)+2/(1+x^2)+4/(1+x^4)=4/(1-x^4)+4/(1+x^4)=8/(1-x^8)1.(2x分之3)+2=02.(x-1分之x)+(x+1分之2)=13.(x+1分之1)-(x²+3x+2分之x²)=-13/2x=-23=-4xx=-3/4x/(x-1)+2/(x+1)=1x(x+1)+2(x-1)=(x-1)(x+1)x^2+x+2x-2=x^2-13x=1x=1/31/(x+1)-x^2/(x^2+3x+2)=-11/(x+1)-x^2/(x+1)(x+2)=-1(x+2)/(x+1)(x+2)-x^2(x+1)(x+2)=-1x+2-x^2=-(x+1)(x+2)x^2-x-2=x^2+3x+24x=-4x=-1拓展:原题=1-1/2+1/2-1/3....+1/99-1/100=1-1/100(2):根据(1)得:1-1/2+1/2-1/3+.....+1/n-1/(n+1)=1-1/(n+1)3.(1)1/1*2+1/2*3+1/3*4+...+1/99*100=(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/99-1/100)=1-1/100=99/100(2)1/1*2+1/2*3+1/3*4+...+1/n(n+1)==(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+[1/n-1/(n+1)]=1-1/(n+1)=n/(n+1)就这么多了。实在不行也没办法!谢谢
2023-01-13 22:55:522

数学高手金,几道简单的初二分式计算题,写明过程就好,题目已在下面截图。

16题,令x/3=y/2=z/5=k,x=3k,y=2k,z=5k,再代到式子里去 15题比较笨的方法就是把y消掉。希望采纳
2023-01-13 22:55:563

解分式方程 (m+2)/(2m-4)÷【m+2-(m+2/m-2)】 是计算题

这不是方程 是代数式化简吧、 首先(m+2)/(2m-4)分母提出2 得(m+2)/ 2(m-2)大括号里面——化成相同分母=【(m+2)(m-2)-(m+2)】/(m-2) =【(m+2)(m-2-1)】/(m-2) =【(m+2)(m-3)】/(m-2)原式=(m+2)/ 2(m-2) ÷...
2023-01-13 22:56:041

分式的计算题

原式=(x-y)/(x+y)+(x+y)(x-y)/(x+y)^2-2=(x-y)/(x+y)+(x-y)/(x+y)-2=2(x-y)/(x+y)-2(x+y)/(x+y)=(2x-2y-2x-2y)/(x+y)=-4y/(x+y)
2023-01-13 22:56:081

分式方程计算题

1.3/2x=-23=-4xx=-3/42.x/(x-1)+2/(x+1)=1x(x+1)+2(x-1)=(x-1)(x+1)x^2+x+2x-2=x^2-13x=1x=1/33.1/(x+1)-x^2/(x^2+3x+2)=-11/(x+1)-x^2/(x+1)(x+2)=-1(x+2)/(x+1)(x+2)-x^2(x+1)(x+2)=-1x+2-x^2=-(x+1)(x+2)x^2-x-2=x^2+3x+24x=-4x=-1x/(2x-1)=(-2x-1)/(1-2x)x=2x+1x=-1(3) (11-2x)/(4-x)=(1-x)/(x-4)11-2x=x-13x=12x=4∵当x=4时,原方程无意义,∴原方程无解7/(x2+x)+3/(x2-x)=6/(x2-1)解方程两边同乘以最简公分母x(x+1)(x-1),得7(x-1)+3(x+1)=6x去括号,得7x-7+3x+3=6x移项,得7x-6x+3x=7-3合并同类项,得4x=4系数化1,得x=13/x-6/(1-x)-(x+5)/x(1-x)=0解方程两边同乘以最简公分母x(1-x),得3(1-x)-6x-(x+5)=0去括号,得3-3x-6x-x-5=0合并同类项,得-10x=2系数化1,得x=-1/5(5x-4)/(2x-4)=(2x+5)/(3x-6)-1/2解方程两边同乘以最简公分母6(x-2),得3(5x-4)=2(2x+5)-3(x-2)去括号,得15x-12=4x+10-3x+6移项,得15x-4x+3x=10+6+12合并同类项,得14x=28系数化1,得x=2经检验,X=2是增根,舍去,所以原方程无解x2-4x/(x2-1)+1=2x/(x+1)解方程两边同乘以最简公分母(x2-1),得x2-4x+x2-1=2x(x-1)即2x2-4x-1=2x2-2x移项,得2x2-4x-2x2+2x=1合并同类项,得-2x=1x=-1/21/(x+3)+1/(6-2x)=(3x-15)/(2x2-18)解方程两边同乘以最简公分母2(x+3)(x-3),得2(x-3)-(x+3)=3x-15去括号,得2x-6-x-3=3x-15移项,得2x-x-3x=-15+6+3合并同类项,得-2x=-6x=3解关于x的方程:x/(x-a)=1-[a/(x+b)](a≠0)解:x/(x-a)+[a/(x+b)]=1通分,(x2+bx+ax-a2)/[(x-a)(x+b)]=1方程两边同乘以最简公分母(x-a)(x+b),得(x2+bx+ax-a2)=(x-a)(x+b)去括号,得x2+bx+ax-a2=x2+bx-ax-ab移项,得x2+bx+ax-x2-bx+ax=-ab+a2合并同类项,得2ax=a2-abx=(a-b)/2希望可以采纳
2023-01-13 22:56:151

分式的计算题,急!!

x/(2x-5)=5/(5-2x) (5-2x)x=5(2x-5)5x-2x^2=10x-252x^2-5x-25=0(x-5)(2x+5)=0x-5=0或2x+5=0x=5或-5/2x/(x-2)+2/(x^2-4)=1x(x+2)+2=x^2-4x^2+2x+2=x^2-42x=-6x=-3
2023-01-13 22:56:182

分式计算题

[(a^2+b^2)(a^2-b^2)-(a-b)(a+b)]*[(a-b)2ab] =[(a^2+b^2)(a+b)(a-b)-(a-b)^2(a+b)(a-b)]*[(a-b)2ab] =[(a^2+b^2-a^2+2ab-b^2)(a+b)(a-b)]*[(a-b)2ab]=[2ab(a+b)(a-b)]*[(a-b)2ab]=1(a+b)
2023-01-13 22:56:212

一道关于分式的数学计算题。。

=x2+(1/(x+y))2+2x(1/(x+y))-x2-(1/(x+y))2+2x(1/(x+y))化简得;=4x/(x+y)
2023-01-13 22:56:246

分式计算题!!!!

前面两项提出来一个二分之一,然后再通分一下应该就行了。
2023-01-13 22:56:323

关于分式的计算题

M呢?去哪里了,被那个没良心的吃掉了
2023-01-13 22:56:412

初二数学分式计算题

1.(x+y)/y-2x/(x+y)+x^3/y(x^2-y^2)2.a/(a-b)+a/(a+b)+2a^2/(a^2+b^2)+4a^4/(a^4+b^4)+8a^8/(a^8+b^8)
2023-01-13 22:56:442

分式加减计算题

2m 3n------- - ------5n²p 4mp²=8m²p/20mn²p²-15n³/20mn²p²=(8m²p-15n³)/(20mn²p²)
2023-01-13 22:56:462