奥利费与其他鸵鸟文中老鸵鸟奥利弗其他所有的鸵鸟的结果是怎样的代表了生活中的那些人?

1 are2 is3 think4 come5 has6 is talking7 is looking8 are listening9 is reading10 dislikes7 list

鸵鸟奥利弗因能客观冷静地看待事物,看待自己而幸免于难,而其他鸵鸟却因不敢正视现实而死于非命.

英语奥林匹克网站上有~!

1、最大的鸟
2、永远向前进
3、生得蛋最大
4、四个脚趾走路
5、可以以把头埋进沙子里使自己什么都看不见

奥利费存活了下来,但是老鸵鸟奥利弗其他所有的鸵鸟因为把头埋到沙子里,最终只剩下白骨和羽毛.

解题思路：假定时间间隔为T分钟，本题要从最差情况考虑：（1）当维佳刚到站就有一辆车开走，这时他要再等接近一个时间间隔T分钟，才能看到第一辆车；同理，当第五辆车开出后再等待接近一个时间间隔T分钟，所以等待的时间间隔最多为6T；（2）当维佳刚到站就有一辆车和他相遇，并且当12分钟结束时，正好又有一辆开出，这时经历了4个时间间隔；综合上面两种情况可以得出：4T≤12＜6T，可得，2＜T≤3；同理，再根据“第二次维佳等了奥利娅20分钟，这段时间内开出了6辆火车；”可得出：5T≤20＜7T，可得，207＜T≤4；所以由，2＜T≤3；207＜T≤4；可得：T=3分钟；30分钟的间隔数为：30÷3=10个或（30-3）÷3=9个，可以看到的车是：10+1=11辆或9+1=10辆；问题得解．

假定时间间隔为T分钟，根据分析可知：
（1）4T≤12＜6T，可得，2＜T≤3；
（2）：5T≤20＜7T，可得，[20/7]＜T≤4；
综合上面两种情况可以得出：时间间隔T只能为3，即T=3分钟；
30分钟的间隔数为：30÷3=10（个）或（30-3）÷3=9（个），
可以看到的车是：10+1=11（辆）或9+1=10（辆）；
答：第三次维佳等了奥利娅30分钟，那么这段时间内可能有10辆或11辆火车开出．

点评：
本题考点： 发车间隔问题．

考点点评： 本题关键是根据前两次的等待时间从最差情况考虑，求出时间间隔T分钟的取值范围．

After readingOliver Twist, I have done a lot of thinking. What impresses me the most isOliver- even though he was mistreated and forced to become a thief, he nevergives up the kindness in heart, which never changes. I guess that’s why throughall those difficulties and troubles, he finally makes it and stays happilyafter with his families.
On the other hand,not all of those liars, frauds and thieves are evil. I believe the old sayingthat all men were born with good nature. In spite of their wrong occupations,they are not that bad in nature as they are accused to be. Mr. Brownlow sets upa great example for us to follow. Despite of the fact that Oliver used to be athief and was caught back to the gangsters when he was delivering a book, whichMr. Brownlow paid five pounds for, Mr. Brownlow still managed to trust and helphim with all heart. It is this precious kindness and righteousness that deserveevery each one of us to learn from.