4x²-6x-(y-2)(y+1)=0分解因式

drygrass2022-10-04 11:39:541条回答

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sjtxlsxz 共回答了20个问题 | 采纳率90%
4x²-6x-(y-2)(y+1)=0
4x²-6x-(y²+y-2y-2)=0
4x²-6x-y²+y+2=0
4(x²-3/2x)-(y²-y)+2=0
4(x²-3/2x+9/16)-9/4-(y²-y+1/4)+1/4+2=0
4(x-3/4)²-(y-1/2)²=0
[2(x-3/4)+(y-1/2)][2(x-3/4)-(y-1/2)]=0
(2x+y-2)(2x-y-1)=0
1年前

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