(1)x^2+9x/x^2+3x+x^2-9/x^2-6x+9 (2)2a/a^2-4-1/a-2

missingmimi2022-10-04 11:39:544条回答

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共4条回复
lhcyhx 共回答了20个问题 | 采纳率90%
(x^2+9x)/(x^2+3x)+(x^2-9)/(x^2-6x+9)
=(x+9)/(x+3)+(x+3)/(x-3)
=2+6/(x+3)+6/(x-3)
=2+12x/(x^2-9)
2a/(a^2-4)-1/(a-2)
=(2a-a-2)/(a^2-4)=1/(a+2)
1年前
草巴哈他kk 共回答了43个问题 | 采纳率
=(x+9)/(x+3)+(x+3)/(x-3)
=2+6/(x+3)+6/(x-3)
=2+12x/(x^2-9)
=(2a-a-2)/(a^2-4)=1/(a+2)
1年前
lauarthur 共回答了20个问题 | 采纳率95%
使用百度Hi可以第一时间收到“提问有新回答”“回答被采纳”“网友求助”的通知。查看详情
1年前
没人问3 共回答了22个问题 | 采纳率90.9%
(1)(x^2+9x)/(x^2+3x)+(x^2-9)/(x^2-6x+9)
=(x+9)/(x+3)+(x+3)/(x-3)
=2+6/(x+3)+6/(x-3)
=2+12x/(x^2-9)
(2)2a/(a^2-4)-1/(a-2)
=(2a-a-2)/(a^2-4)=1/(a+2)
仅供参考 ,谢谢合作!
1年前

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x^2+9x/x^2+3x+x^2-9/x^2+6x+9
ufodxx1年前1
Verseau24 共回答了22个问题 | 采纳率95.5%
=x(x+9)/x(x+3)+(x+3)(x-3)/(x+3)²
=(x+9)/(x+3)+(x-3)/(x+3)
=(x+9+x-3)/(x+3)
=2(x+3)/(x+3)
=2

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