(-3x^2)^3*(-4y^3)^2/(6x^2y)^3怎么算

yaoxiong182022-10-04 11:39:541条回答

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蓝雨83 共回答了23个问题 | 采纳率82.6%
(-3x^2)^3*(-4y^3)^2/(6x^2y)^3
=(-27x^6)*(16y^6)/(216x^6y^3)
=(-27*16/216)x^(6-6)y^(6-3)
=-2y^3
1年前

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