xo^2=a^2b^2/(k^2a^2+b^2)怎么计算的?

gancao111662022-10-04 11:39:541条回答

xo^2=a^2b^2/(k^2a^2+b^2)怎么计算的?
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ivy_vain 共回答了16个问题 | 采纳率93.8%
设直线OQ的方程为:y=kx
设Q点为(x0,kx0),则:x0^2/a^2+k^2x0^2/b^2=1
即:x0^2(1/a^2+k^2/b^2)=x0^2((b^2+k^2a^2)/(a^2b^2))=1
即:x0^2=a^2b^2/(k^2a^2+b^2)
1年前

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