1.（ab+1)^2-(ab-1)^2

lygang122022-10-04 11:39:544条回答

1.（ab+1)^2-(ab-1)^2
2.(3mn+1)(3mn-1)-8m^2n^2
3.(x+2)^2-(x+5)(x-1)
4.(x-2)^2-2(x+1)(x-1)
5.(x+2)^2-(3x+1)(x-1)
6.(-2a+10b)(2a+10b)

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=(ab+1+ab-1)(ab+1-ab+1)=4ab
2.(3mn+1)(3mn-1)-8m^2n^2
=9m^2n^2-1-8m^2n^2
=m^2n^2-1
3.(x+2)^2-(x+5)(x-1)
=x^2+4x+4-x^2-4x+5
=9
4.(x-2)^2-2(x+1)(x-1)
=x^2-4x+4-2x^2+1
=-x^2-4x+5
=(x+5)(1-x)
5.(x+2)^2-(3x+1)(x-1)
=x^2+4x+4-3x^2+2x+1
=-2x^2+6x+5
6.(-2a+10b)(2a+10b)
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=(ab+1+ab-1)(ab+1-ab+1)
=2ab*2
=4ab
2.(3mn+1)(3mn-1)-8m^2n^2
=9m^2n^2-1-8m^2n^2
=m^2n^2-1
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(ab+1)^2-(a+b)^2
=(ab+1+a+b)(ab+1-a-b)
=[a(b+1)+(b+1)][a(b-1)-(b-1)]
=(a+1)(b+1)(a-1)(b-1)

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=(3m-1)²-(n-1)²
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=(3m+n-2)(3m-n)
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=(2x-1/2)²-9y²
=(2x-1/2 +3y)(2x-1/2 -3y)
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