-3x+6x^2-3x^3怎么计算

既然要详细解答,那我就一步一步写给你看吧：
原式=-(3x-6x^2+3x^3)
=-x(3x^2-6x+3)
=-3x(x^2-2x+1)
=-3x(x-1)^2
原式=a^2(a-3)-(a-3)
=(a-3)(a^2-1)
=(a-3)(a+1)(a-1)
记得哈,因式分解的时候要先提公因式,再根据完全平方公式或平方差公式进行分解,甚至可以用十字交叉法来分解.呐,这种题多练练就好了!

-6x^2+12x-3=0
x^2-2x+1/2=0
x^2-2x+1=1/2
(x-1)^2=1/2
x=1+√2/2或x=1-√2/2

F'(x)=-6x^2+12x-3
令 -6x^2+12x-3=0
2x^2-4x+1=0
解出x1=1+√ 2/2 x2=1-√ 2/2
f(x1)=-1-3√ 2,f(x2)=-1+3√ 2
f(-1)=15 f(2)=6
所以最大值是15,最小值是-1-3√ 2

1.1/2p^2-2pq
=p(p/2-2q)
2.-3x+6x^2-3x^3
=-3x(x^2+2x+1)
=-3x(x+1)^2
3.a^2（a-3)-a+3
=a^2(a-3)-(a-3)
=(a^2-1)(a-3)
=(a+1)(a-1)(a-3)
4.2xy-x^2-y^2+1
=-(x^2-2xy+y^2)+1
=1-(x-y)^2
=(1-x+y)(1+x-y)