sin^4a-cos^4a=sin^2a-cos^2a

zhangxiaoliang192022-10-04 11:39:541条回答

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邻比若 共回答了17个问题 | 采纳率82.4%
sin^4a-cos^4a=(sin^2a-cos^2a)(sin^2a+cos^2a)=(sin^2a-cos^2a)*1=sin^2a-cos^2a
1年前

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