2x/9-x05+1/x-3-x05+6x+9怎么写

胡骁2022-10-04 11:39:541条回答

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忍无可忍才发言1 共回答了25个问题 | 采纳率100%: 2x/(9-x²)+1/(x-3)-1/(x²+6x+9)
=-2x/(x-3)(x+3)+(x+3)/(x-3)(x+3)-1/(x²+6x+9)
=(-2x+x+3)/(x-3)(x+3)-1/(x²+6x+9)
=(3-x)/(x-3)(x+3)-1/(x+3)²
=-1/(x+3)-1/(x+3)²
=(-x-3-1)/(x+3)²
=(-x-4)/(x+3)²; 1年前

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