我爱看《儿童时代》 《儿童故事选》和 课外书.这个病句怎么改呢?

我们中队图书角里有《中国少年报》《儿童时代》《故事大王》《红领巾》等.
注明:书名号与书名号之间不用顿号!

把杂志改书报

他订了很多报刊杂志,其中包括《儿童时代》.
《儿童时代》也是报纸杂志的一种,重复

解题思路：根据排列组合知识可得，三种报纸一共有3+3+1=7种订法；把7种不同的订法看作7个抽屉，把订报纸的人数看作元素，从最不利情况考虑，根据“他们中至少有6个订的报纸杂志完全相同．”，先在每个抽屉需要放5个元素，共需要5×7=35个，再取出1个不论是哪种订法，总有一个抽屉里的订法和它相同，所以至少需要取出：35+1=36（个）元素，也就是最少需要36人，据此解答．

根据分析可得，
三种报纸一共有3+3+1=7种订法；
5×7+1=36（人）；
答：这个班最少有36人．
故答案为：36．

点评：
本题考点： 抽屉原理．

考点点评： 本题是排列组合与抽屉原理问题的综合应用；抽屉原理问题的解答思路是：要从最不利情况考虑，准确地建立抽屉和确定元素的总个数，然后根据“至少数=元素的总个数÷抽屉的个数+1（有余数的情况下）”解答，本题需要把“至少数=元素的总个数÷抽屉的个数+1（有余数的情况下）”这个知识点逆用，属于比较难的题．

"Childhood" the editors, are called me to write one to the child "My Childhood". About “the childhood”, I wrote have continued one. Now might as well tells thrilling stories, listens for the children. this was probably about 1906 matter, my father was the battalion commander who at that time the Yantai Navy practiced the camp, our family lived in practices in a camp opposite staff family member's central courtyard, this central courtyard was covers on a flat land which dug from the hillside. I always remembered that daily my mother combs the short braid for me time, I from the rear window look, outside is a high dirt wall, in each hoe has dug in the concave hole, steadily young Cong dandelion, she is “the flower which” in my life becomes friends with in friend's first! when my family following hillside, some and the marine warship passes the flag indicator flag Taiwan, my father brings a flagstone - - was we go to school in childhood to use frequently to make the arithmetic that kind of flagstone - - and is leading two colored flag sailors, on flag Taiwan went with the harbor in the warship telephone conversation. Yantai Dongshan at that time, is bleak very, often has the wolf to come out in the night to look for food. Our kitchen master worker often complained: Last night covered under the big chicken coop, above was also pressing a big stone chicken coop, also goes against by the wolf, ate the chicken. Was inferior that builds a brick the hen house to be good. I have not seen the wolf, also on toward has not gone to at heart this saying.
One day of evening, the father also leads a flag signaling sailor, on flag Taiwan went. The sailor got down quite a while, the father also on the stage, I ran flag Taiwan to look for the father. Dim light of night boundless, I hear after death as if to have an airedale in with me, hears father one to shout at suddenly: “you come up quickly!”I turn head when looked, sees only, ash blue eye which a pair is also bright is cool penetrates to the bone, simultaneously on the flag stage a sound of something being struck or falling to the ground bang, is the flagstone falls in the ground broken sound, that airedale resembles, some pair of fearful ash blue eye's thing, is towing a long tail, turned around to run. All these only occur in several seconds time! I ran flag Taiwan, the father closely have hugged me in the bosom said: “what pursued a moment ago behind you are a wolf! Was not I pounds the flagstone to run away in fear it, you already let it eat. Later at such late time does not want to come out, to hear?”I was only at that time hee hee am smiling in the father bosom, I could not imagine am nipped by the wolf have been eating am any feeling. Now recalled after actually has one kind “, fears”.

“战场上短暂的安静.”修改病句
改为；战场上出现了短暂的安静.
《中国少年报》和《儿童时代》这两种报纸我都爱看.
改为；《中国少年报》和《儿童时代》这两种读物我都爱看.

解题思路：根据排列组合知识可得，三种报纸一共有3+3+1=7种订法；把7种不同的订法看作7个抽屉，把订报纸的人数看作元素，从最不利情况考虑，根据“他们中至少有6个订的报纸杂志完全相同．”，先在每个抽屉需要放5个元素，共需要5×7=35个，再取出1个不论是哪种订法，总有一个抽屉里的订法和它相同，所以至少需要取出：35+1=36（个）元素，也就是最少需要36人，据此解答．

根据分析可得，
三种报纸一共有3+3+1=7种订法；
5×7+1=36（人）；
答：这个班最少有36人．
故答案为：36．

点评：
本题考点： 抽屉原理．

考点点评： 本题是排列组合与抽屉原理问题的综合应用；抽屉原理问题的解答思路是：要从最不利情况考虑，准确地建立抽屉和确定元素的总个数，然后根据“至少数=元素的总个数÷抽屉的个数+1（有余数的情况下）”解答，本题需要把“至少数=元素的总个数÷抽屉的个数+1（有余数的情况下）”这个知识点逆用，属于比较难的题．

我们中队图书室里有《中国少年报》、《儿童时代》、《十万个为什么》等杂志.
《中国少年报》是报纸,《十万个为什么》是书籍.
改为：我们中队图书室里有《中国少年报》、《儿童时代》、《十万个为什么》等阅读资料.

解题思路：由“买钢笔又用去第二次剩下的钱的一半多1元，最后还剩4元”，假设买钢笔又用去第二次剩下的钱的一半，则还剩下1+4=5（元），因此第二次剩下的钱数为：（4+1）×2=10（元）；由“又用剩下的钱的一半买了一本《儿童时代》”，此时剩下10元，则10元占剩下的钱的一半，则第一次用去4元后剩下10×2=20（元），然后加上第一次用去的4元，解决问题．

（4+1）×2×2+4
=5×2×2+4
=20+4
=24（元）
答：小丽原有24元．
故答案为：24．

点评：
本题考点： 逆推问题．

考点点评： 解决此类问题的关键是抓住最后得到的数量，从后向前进行推理，根据加减乘除的逆运算思维进行解答．

解题思路：根据排列组合知识可得，三种报纸一共有3+3+1=7种订法；把7种不同的订法看作7个抽屉，把订报纸的人数看作元素，从最不利情况考虑，根据“他们中至少有6个订的报纸杂志完全相同．”，先在每个抽屉需要放5个元素，共需要5×7=35个，再取出1个不论是哪种订法，总有一个抽屉里的订法和它相同，所以至少需要取出：35+1=36（个）元素，也就是最少需要36人，据此解答．

根据分析可得，
三种报纸一共有3+3+1=7种订法；
5×7+1=36（人）；
答：这个班最少有36人．
故答案为：36．

点评：
本题考点： 抽屉原理．

考点点评： 本题是排列组合与抽屉原理问题的综合应用；抽屉原理问题的解答思路是：要从最不利情况考虑，准确地建立抽屉和确定元素的总个数，然后根据“至少数=元素的总个数÷抽屉的个数+1（有余数的情况下）”解答，本题需要把“至少数=元素的总个数÷抽屉的个数+1（有余数的情况下）”这个知识点逆用，属于比较难的题．

4+1=5（元）,这是买钢笔剩下的钱,因为买钢笔用去了剩下的钱的一半,所以买钢笔用了五元,则5+5=10（元）,而这是买《儿童时代》的钱剩下的,《儿童时代》用了10元,10+10=20（元）.再加上买《童话大王》的五元,则小青一开始有20+5=25（元）

你好,很高兴回答你的问题

改成：我爱看《儿童文学》、《少年文艺》等课外书和《小学生学习报》等报刊.

解析：报纸不属于课外书