(5^lg20)[(1/2)^lg0.5]=(5^lg20)[(5/10)^lg0.5]=(5^lg20)(5^lg0.

sgy17102022-10-04 11:39:541条回答

(5^lg20)[(1/2)^lg0.5]=(5^lg20)[(5/10)^lg0.5]=(5^lg20)(5^lg0.5/10^lg0.5)=2*5^(lg20+lg0.5)=10
最后一步是怎么得到的呢?

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清吟浅唱共回答了23个问题 | 采纳率91.3%: (5^lg20)*(5^lg0.5)=5^(lg20+lg0.5),10^lg0.5=1/2.
(5^lg20)(5^lg0.5/10^lg0.5)
=(5^lg20)*(5^lg0.5)/10^lg0.5
=2[5^(lg20+lg0.5)]
=2*5^(lg20+lg0.5); 1年前