xy分之x+y-yz分之y+z

killet_0142022-10-04 11:39:541条回答

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lemon2132 共回答了24个问题 | 采纳率83.3%: (x+y)/xy-(y+z)/yz=[(x+y)z-(y+z)x]/xyz
=(xz+yz-xy-xz)/xyz
=(yz-xy)/xyz
=(z-x)/xz; 1年前

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干什么?计算吗?
原式=x/y
(x²-y²)/(xy)-(xy-y²)/(xy-x²)
=(x²-y²)/(xy)-y(x-y)/[x(y-x)]
=(x+y)(x-y)/(xy)+y(x-y)/[x(x-y)]
=[(x-y)/x][(x+y)/y+y/(x-y)]
=[(x-y)/x][(x+y)(x-y)+y²]/[y(x-y)]
=[(x-y)/x](x²-y²+y²)/[y(x-y)]
=[(x-y)/x]{x²/[y(x-y)]}
=[(x-y)x²]/[xy(x-y)]
=x/y
为了满足楼主“要过程‘的要求,是楼主看清楚解题思路,上边写得比较啰嗦.

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