(6x+12)/(x^2+4x+4)+(x^2)/(x^2-4)=(x^2-4)/(x^2-4x+4)

fengqiaoyepo052022-10-04 11:39:542条回答

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giggle_wang 共回答了12个问题 | 采纳率91.7%: 6(x+2)/(x+2)²+x²/(x+2)(x-2)=(x+2)(x-2)/(x-2)²
6/(x+2)+x²/(x+2)(x-2)=(x+2)/(x-2)
两边乘(x+2)(x-2)
6x-12+x²=x²+4x+4
6x-12=4x+4
x=8
经检验,x=8是方程的解; 1年前

kele0111 共回答了104个问题 | 采纳率: x=8; 1年前

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(6x+12)/(x^2+4x+4)+(4-x^2)/(x^2-4x+4)=(x^2)/(4-x^2) (6x+12)/(x^2+4x+4)+(4-x^2)/(x^2-4x+4)=(x^2)/(4-x^2) 哎呦亲们帮帮忙吧.我受不了了 stja1年前2: 殷切殷切共回答了15个问题 | 采纳率93.3%

化简左式：
(6x+12)/(x^2+4x+4)+(4-x^2)/(x^2-4x+4)
=6(x+2)/(x+2)²+(2+x)(2-x)/(x-2)²
=6/(x+2)-(x+2)/(x-2)
=6(x-2)/[(x+2)(x-2)]-(x+2)²/[(x+2)(x-2)]
=6(x+2)/(x²-4)-(x+2)²/(x²-4)
=(2x-x²-16)/(x²-4)
=(x²-2x+16)/(4-x²)
∵左式=右式
∴(x²-2x+16)/(4-x²)=x²/(4-x²)=
∴x²-2x+16=x²
∴x=8

1年前查看全部

(6x+12)/(x+2)^ - (x^-4)/(x-2)^ + x^/x^-4 =0 (6x+12)/(x+2)^ - (x^-4)/(x-2)^ + x^/x^-4 =0 化简求值 天天333871年前3: luoyixue99 共回答了12个问题 | 采纳率100%

(6x+12)/(x+2)^=6(x+2)/(x+2)^=6/(x+2)
(x^-4)/(x-2)^=(x-2)(x+2)/(x-2)^=(x+2)/(x-2)
所以,(6x+12)/(x+2)^ - (x^-4)/(x-2)^
=6/(x+2)-(x+2)/(x-2)
通分,=[6(x-2)-(x+2)^]/(x^-4)
=(6x-12-x^-4x-4)/(x^-4)
=(-x^+2x-16)/(x^-4)
所以,(-x^+2x-16)/(x^-4)+x^/(x^-4)=0
(2x-16)/(x^-4)=0
2x-16=0
x=8

1年前查看全部

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