(0.25a^2b-2/1a^3b^2-6/1a^4b^3)/(-0.25a^2b)

qq4747286152022-10-04 11:39:541条回答

(0.25a^2b-2/1a^3b^2-6/1a^4b^3)/(-0.25a^2b)
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空螺螺共回答了17个问题 | 采纳率88.2%: (0.25a^2b-2/1a^3b^2-6/1a^4b^3)/(-0.25a^2b)
=-1+2ab+2/3a²b²
=(2/3)(a²b²+3ab-3/2)
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如果本题有什么不明白可以追问,; 1年前

有这样一道题"当a=2,b=-2时,求多项式3a^3b^3-0.5a^2b+b-(4a^3b^3-0.25a^2b)+( 有这样一道题"当a=2,b=-2时,求多项式3a^3b^3-0.5a^2b+b-(4a^3b^3-0.25a^2b)+(a^3b^3+0.25a^2b)-2b^2+3的值",马小虎做题时把a=2错抄成a=-2,王小真没抄错题,但他们做出的结果却都一样,你知道这是怎么回事吗?说明理由 ^是平方 c00591年前4: fzustar 共回答了19个问题 | 采纳率89.5%

3a^3b^3-0.5a^2b+b-(4a^3b^3-0.25a^2b)+(a^3b^3+0.25a^2b)-2b^2+3=3a^3b^3-0.5a^2b+b-4a^3b^3+0.25a^2b+a^3b^3+0.25a^2b-2b^2+3=(3a^3b^3-4a^3b^3+a^3b^3)+(-0.5a^2b+0.25a^2b+0.25a^2b)+b-2b^2+3=b-2b^2+3,多项式的...

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