因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11（a为常数）

jiayi200509142022-10-04 11:39:541条回答

因式分解2x^3+(2a+23)x^2+(10-7a)x+3a-11（a为常数）
答案为(2x-1)(x^2+(a+12)+11-3a)

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我a爱我家共回答了17个问题 | 采纳率94.1%: 2x^3+(2a+23)x^2+(10-7a)x+3a-11
=2x^3-x^2+x^2+(2a+23)x^2+(10-7a)x+3a-11
=x^2*(2x-1)+(2a+24)x^2-(a+12)x+(a+12)x+(10-7a)x+3a-11
=x^2*(2x-1)+(a+12)x(2x-1)+(22-6a)x-(11-3a)
=x^2*(2x-1)+(a+12)x(2x-1)+(11-3a)(2x-1)
=(2x-1)(x^2+(a+12)+11-3a).; 1年前

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