友谊商场用7万元购进60台电视机,甲种：1100元每台 乙种：1300元每台 丙种：2100元每台,求进货方案

One day in the morning at ten o'clock,I was on my way to the cinema when I met with a pair of American couples.They wondered how to get to the Youyi Department Store and felt very anxious.Therefore,I take the initiative to tell them how can they get there.Then they were thankful to me.Although I was late for the movie,I didn't care about it for that I was happy that I could talk with foreigners.
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2月份:10乘2+1=21万元
3月份：10乘3-4=28万元
第一季度：21+28+10 =59 万元

解题思路：（1）降价1元，可多售出10件，降价x元，可多售出10x件，盈利的钱数=原来的盈利-降低的钱数；
（2）等量关系为：每件商品的盈利×可卖出商品的件数=2240，把相关数值代入计算得到合适的解即可．

（1）（20-x），10x
（2）根据题意得：（20-x）（100+10x）=2240，
整理得，x²-10x+24=0，
解得x₁=4，x₂=6
答：每件商品降价4或6元时，商场日盈利可达到2240元．

点评：
本题考点： 一元二次方程的应用．

考点点评： 考查一元二次方程的应用；得到可卖出商品数量是解决本题的易错点；得到总盈利2240的等量关系是解决本题的关键．