2c/bd与3ac/4b^2通分 2xy/(x+y)^2与x/x^2-y^2 求过程和最简公分母

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ai7481 共回答了19个问题 | 采纳率89.5%
2c/bd与3ac/4b^2通分
2c/bd=2c*4b/(4b^2*d)=8bc/(4b^2*d)
3ac/4b^2=3ac/(4b^2*d)
2xy/(x+y)^2与x/x^2-y^2 求过程和最简公分母
2xy/(x+y)^2=2xy*(x-y)/[(x+y)^2*(x-y)]
x/x^2-y^2=x/[(x+y)*(x-y)]=x*(x+y)/[(x+y)^2*(x-y)]
最简公分母:[(x+y)^2*(x-y)]
1年前

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