SEGMENT TOO LARGE 错误

yzxl992022-10-04 11:39:541条回答

SEGMENT TOO LARGE 错误
C51 COMPILER V6.23a - SN:K1RIP-M2192E
COPYRIGHT KEIL ELEKTRONIK GmbH 1987 - 2002
C51 COMPILATION COMPLETE.0 WARNING(S),1 ERROR(S)
ERROR C249 IN LINE 92 OF CHESHI1.C:'DATA':SEGMENT TOO LARGE
编译/汇编过程中发现错误.
汇编/编译发现错误!终止!
#include
sbit dir=P1^0;
sbit rl=P1^1;
sbit ll=P1^2;
sbit cp=P2^7;
sbit h1=P1^3;
sbit h2=P1^4;
sbit l1=P1^5;
sbit l2=P1^6;
sbit l3=P1^7;
sbit l4=P2^0;
sbit sb1=P2^1;//开始
sbit sb2=P2^2;//待机
sbit sb3=P2^3;//正
sbit sb4=P2^4;//反
sbit sb5=P2^5;//+
sbit sb6=P2^6;//-
#define dat P0
unsigned char a[][16]=
{
0x08,0x18,0xC8,0x14,0x32,0x11,0xE8,0x08,0x0C,0xEA,0x08,0x88,0x88,0x08,0x08,0x08,
0x02,0x02,0x3F,0x02,0x02,0x02,0x7F,0x08,0x08,0x7F,0x08,0x08,0x08,0x08,0x0A,0x04,/*"待",0*/
0x08,0x08,0x08,0x7F,0x08,0x08,0x1C,0x2C,0x2A,0x0A,0x89,0x88,0x48,0x48,0x28,0x08,
0x00,0x1F,0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x10,0x50,0x50,0x50,0x60,0x00,/*"机",1*/
};
unsigned char b[][16]=
{
0x00,0xFE,0x00,0x00,0x00,0x00,0x08,0x08,0x08,0x08,0x08,0x08,0x08,0xFF,0x00,0x00,
0x00,0x7F,0x01,0x01,0x01,0x01,0x01,0x3F,0x01,0x01,0x01,0x01,0x01,0x7F,0x00,0x00,/*"正",0*/
0x00,0xFC,0x04,0x04,0xFC,0x14,0x14,0x24,0x24,0x44,0x84,0x84,0x42,0x32,0x0D,0x00,
0x1E,0x01,0x00,0x00,0x0F,0x08,0x08,0x04,0x04,0x02,0x01,0x01,0x06,0x38,0x10,0x00,/*"反",1*/
};
unsigned char c[][16]=
{
0x00,0x00,0x00,0x18,0x24,0x42,0x42,0x42,0x42,0x42,0x42,0x42,0x24,0x18,0x00,0x00,/*"0",0*/
0x00,0x00,0x00,0x08,0x0E,0x08,0x08,0x08,0x08,0x08,0x08,0x08,0x08,0x3E,0x00,0x00,/*"1",1*/
0x00,0x00,0x00,0x3C,0x42,0x42,0x42,0x20,0x20,0x10,0x08,0x04,0x42,0x7E,0x00,0x00,/*"2",2*/
0x00,0x00,0x00,0x3C,0x42,0x42,0x20,0x18,0x20,0x40,0x40,0x42,0x22,0x1C,0x00,0x00,/*"3",3*/
0x00,0x00,0x00,0x20,0x30,0x28,0x24,0x24,0x22,0x22,0x7E,0x20,0x20,0x78,0x00,0x00,/*"4",4*/
0x00,0x00,0x00,0x7E,0x02,0x02,0x02,0x1A,0x26,0x40,0x40,0x42,0x22,0x1C,0x00,0x00,/*"5",5*/
0x00,0x00,0x00,0x38,0x24,0x02,0x02,0x1A,0x26,0x42,0x42,0x42,0x24,0x18,0x00,0x00,/*"6",6*/
0x00,0x00,0x00,0x7E,0x22,0x22,0x10,0x10,0x08,0x08,0x08,0x08,0x08,0x08,0x00,0x00,/*"7",7*/
0x00,0x00,0x00,0x3C,0x42,0x42,0x42,0x24,0x18,0x24,0x42,0x42,0x42,0x3C,0x00,0x00,/*"8",8*/
0x00,0x00,0x00,0x18,0x24,0x42,0x42,0x42,0x64,0x58,0x40,0x40,0x24,0x1C,0x00,0x00,/*"9",9*/
};
void delay(int i)
{
int a,s;
for(a=0;a

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美丽的水仙花 共回答了15个问题 | 采纳率93.3%
unsigned char a[][16]=
{
0x08,0x18,0xC8,0x14,0x32,0x11,0xE8,0x08,0x0C,0xEA,0x08,0x88,0x88,0x08,0x08,0x08,
0x02,0x02,0x3F,0x02,0x02,0x02,0x7F,0x08,0x08,0x7F,0x08,0x08,0x08,0x08,0x0A,0x04,/*"待",0*/
0x08,0x08,0x08,0x7F,0x08,0x08,0x1C,0x2C,0x2A,0x0A,0x89,0x88,0x48,0x48,0x28,0x08,
0x00,0x1F,0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x11,0x10,0x50,0x50,0x50,0x60,0x00,/*"机",1*/
};
unsigned char b[][16]=
{
0x00,0xFE,0x00,0x00,0x00,0x00,0x08,0x08,0x08,0x08,0x08,0x08,0x08,0xFF,0x00,0x00,
0x00,0x7F,0x01,0x01,0x01,0x01,0x01,0x3F,0x01,0x01,0x01,0x01,0x01,0x7F,0x00,0x00,/*"正",0*/
0x00,0xFC,0x04,0x04,0xFC,0x14,0x14,0x24,0x24,0x44,0x84,0x84,0x42,0x32,0x0D,0x00,
0x1E,0x01,0x00,0x00,0x0F,0x08,0x08,0x04,0x04,0x02,0x01,0x01,0x06,0x38,0x10,0x00,/*"反",1*/
};
unsigned char c[][16]=
{
0x00,0x00,0x00,0x18,0x24,0x42,0x42,0x42,0x42,0x42,0x42,0x42,0x24,0x18,0x00,0x00,/*"0",0*/
0x00,0x00,0x00,0x08,0x0E,0x08,0x08,0x08,0x08,0x08,0x08,0x08,0x08,0x3E,0x00,0x00,/*"1",1*/
0x00,0x00,0x00,0x3C,0x42,0x42,0x42,0x20,0x20,0x10,0x08,0x04,0x42,0x7E,0x00,0x00,/*"2",2*/
0x00,0x00,0x00,0x3C,0x42,0x42,0x20,0x18,0x20,0x40,0x40,0x42,0x22,0x1C,0x00,0x00,/*"3",3*/
0x00,0x00,0x00,0x20,0x30,0x28,0x24,0x24,0x22,0x22,0x7E,0x20,0x20,0x78,0x00,0x00,/*"4",4*/
0x00,0x00,0x00,0x7E,0x02,0x02,0x02,0x1A,0x26,0x40,0x40,0x42,0x22,0x1C,0x00,0x00,/*"5",5*/
0x00,0x00,0x00,0x38,0x24,0x02,0x02,0x1A,0x26,0x42,0x42,0x42,0x24,0x18,0x00,0x00,/*"6",6*/
0x00,0x00,0x00,0x7E,0x22,0x22,0x10,0x10,0x08,0x08,0x08,0x08,0x08,0x08,0x00,0x00,/*"7",7*/
0x00,0x00,0x00,0x3C,0x42,0x42,0x42,0x24,0x18,0x24,0x42,0x42,0x42,0x3C,0x00,0x00,/*"8",8*/
0x00,0x00,0x00,0x18,0x24,0x42,0x42,0x42,0x64,0x58,0x40,0x40,0x24,0x1C,0x00,0x00,/*"9",9*/
};
直接寻址的东西太多了 把这些移点到子程序里去 就好了
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物理地址=段基址*16+偏移量
VS2010上没有问题,交上去一直Runtime Error(Segment Fault),求指导
VS2010上没有问题,交上去一直Runtime Error(Segment Fault),求指导
代码:
#include
#include
#include
int main()
{
char s[20],line[205],last[10];
int len,i;
while(1)
{
scanf("%s",s);
fflush(stdin);
if(!strcmp(s,"ENDOFINPUT")) break;
//scanf("%[^n]s",line);
gets(line);
fflush(stdin);
scanf("%s",last);
fflush(stdin);
len=strlen(line);
for(i=0;i='A'&&line[i]='F')
{
line[i]-=5;
}
else
{
line[i]=line[i]-4+'Z'-'A';
}
}
}
printf("%sn",line);
}
return 0;
}
Description
Julius Caesar lived in a time of danger and
intrigue.The hardest situation Caesar ever faced was keeping himself
alive.In order for him to survive,he decided to create one of the
first ciphers.This cipher was so incredibly sound,that no one could
figure it out without knowing how it worked.
You are a sub captain of Caesar's army.It is your job to decipher the
messages sent by Caesar and provide to your general.The code is simple.
For each letter in a plaintext message,you shift it five places to the
right to create the secure message (i.e.,if the letter is 'A',the
cipher text would be 'F').Since you are creating plain text out of
Caesar's messages,you will do the opposite:
Cipher text
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Plain text
V W X Y Z A B C D E F G H I J K L M N O P Q R S T U
Only letters are shifted in this cipher.Any non-alphabetical character
should remain the same,and all alphabetical characters will be upper
case.
Input
Input to this problem will consist of a
(non-empty) series of up to 100 data sets.Each data set will be
formatted according to the following description,and there will be no
blank lines separating data sets.All characters will be uppercase.
A single data set has 3 components:
Start line - A single line,"START"
Cipher message - A single line containing from one to two hundred
characters,inclusive,comprising a single message from Caesar
End line - A single line,"END"
Following the final data set will be a single line,"ENDOFINPUT".
Output
For each data set,there will be exactly one line of output.This is the original message by Caesar.
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-----------------------------------
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