cos1°+cos2°+cos3°+.+cos359°等于多少.

laiyuepeng2022-10-04 11:39:545条回答

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aidewenhou 共回答了20个问题 | 采纳率95%: cos1°=cos359° cos2°=cos358°
原题化为(cos1°+cos2°+...cos179°)*2+cos180°
cos1°+cos179°=0
cos2°+cos178°=0
cos90°=0
所以答案是1; 1年前

shang4496947 共回答了43个问题 | 采纳率: cosx + cos(pi+x) = cosx - cosx = 0;
原式 = (cos1 + cos 181) + ... + (cos179 + cos359) + cos180
= cos180 = -1.; 1年前

dfcxc 共回答了17个问题 | 采纳率: 因cos(x)+cos(x+PI)=＝cos(x)+cos(x)cos(PI)-sin(x)sin(PI)=0;
所以原式＝0; 1年前

S_PB 共回答了365个问题 | 采纳率: 0
cos1+cos2+...+cos90与cos271+cos272+...+cos359相消为0
cos91+cos92+...+cos180与cos181+cos182+...+cos270相消为0; 1年前

xinyi3216 共回答了155个问题 | 采纳率: 0
00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000O000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000,
试试从其中找出个O来。; 1年前

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