若x,y∈R,(x+y)^2i+6i-x=-y+5(x+y)i-1,求x和y的值

(x+y)²i+6i-x=-y+5(x+y)i-1
[(x+y)²+6]i-x=5(x+y)i-y-1
则：
(x+y)²+6=5(x+y)
-x=-y-1
即：
(x+y)²+6=5(x+y) ①
x=y+1 ②
把②代人①
(y+1+y)²+6=5(y+1+y)
(2y+1)²+6=5(2y+1)
4y²+4y+1+6=10y+5
4y²-6y+2=0
2y²-3y+1=0
(2y-1)(y-1)=0
y=1/2 或 y=1
解得：
x1=3/2 x2=2
y1=1/2 y2=1