Two boys,Dudi and Gani ,run back and forth between two point
精灵小弟2022-10-04 11:39:541条回答
Two boys,Dudi and Gani ,run back and forth between two points A and B at a constant speed .
Two boys,Dudi and Gani ,run back and forth between two points A and B at a constant speed without stopping.Dudi's speed is 1.5 times Gani's speed.Dudi runs from A to B while Gani from B to A.They both start at the same time.The two same time.The two boys from A when they meet for the first time at 800 meters away from B.how far are the boys from Awhen thwy meet for the second time?
翻译并解答.麻烦各位了.如果很满意会加100分.
最后一句“Awhen" 是”A when“
Two boys,Dudi and Gani ,run back and forth between two points A and B at a constant speed without stopping.Dudi's speed is 1.5 times Gani's speed.Dudi runs from A to B while Gani from B to A.They both start at the same time.The two same time.The two boys from A when they meet for the first time at 800 meters away from B.how far are the boys from Awhen thwy meet for the second time?
翻译并解答.麻烦各位了.如果很满意会加100分.
最后一句“Awhen" 是”A when“
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wrqw1 共回答了16个问题 |采纳率75%- 很高兴为您
两个男孩,Dudi和Gani,跑个来回A和B两点之间以一个恒定的速度没有停下脚步.Dudi 1.5倍的速度是Gani的速度.从A到B Dudi运行时从A.They Gani B两个先发,在同一时间内.这两所花的时间相同.这两个男孩从第一次见面时,他们在800米远的孩子B.how路程Awhen它们却第二次见面吗? - 1年前
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- The boys,Dudi and Gani,run back and forth between two points
The boys,Dudi and Gani,run back and forth between two points A and B at a constant speed without stopping.Dudi,s speed is 1.5 times Gani,s speed.Dudi runs from A to B while Gani from B to A.They both start at the same time.the two boys meet for the first time at 800 meters away from B.How far are the bots from A when they meet for the second time?翻译并解答,事后必有重谢!一塌糊涂呀1年前1
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诺诺不怕 共回答了21个问题
|采纳率90.5%两个男孩,Dudi和Gani,在A和B两点之间以不变的速度来回奔跑.Dudi的速度是Gani的1.5倍.Dudi从A点出发往B点跑,Gani从B点出发往A点跑.两人同时起跑.两人第一次相遇是在离B点800米处.问题：当他们第二次相遇时,他们离A点的距离是多少?
两人第一次相遇时距B点800米,也就是说Gani跑了800米,又因为Dudi的速度是Gani的1.5倍,所以这时Dudi跑了800*1.5=1200米,即两人第一次相遇的地方距A点1200米,也就是说A、B两点相距800+1200=2000米
从第一次相遇到第二次相遇,两人加起来总共要跑的长度是A、B两点距离的2倍,即4000米.又因为Dudi速度是Gani的1.5倍,所以Dudi要跑的长度也是Gani的1.5倍,即Dudi要跑2400米,Gani要跑1600米.
现在我们看看Gani的1600米是怎么跑的.首先他要从两人第一次相遇的地方继续向A点跑,然后从A点折回向B点跑.因为两人第一次相遇的地方距离A点1200米,所以两人第二次相遇的地方距离A点1600-1200=400米.
答案是400米1年前查看全部
- 英语翻译1、The boys,Dudi and Gani,run back and forth between two
英语翻译
1、The boys,Dudi and Gani,run back and forth between two points A and B at a constant speed without shopping.Dudi's speed is 1.5 times Gani's speed.Dudi runs from A to B while Gani from B to A.They both start at the same time.The two boys meet for the first time at 800 meters away from B.How far are the boys from A when they meet for the second time?
2、 The number of the boys in a school is seventy-two more than one third of total number of students of the school .While the number of the girls is twenty less than three fifths of than of total number.how many boys and girls are there in the school?wangjunhong1年前3 -
romanth 共回答了14个问题
|采纳率92.9%1、两个小孩在a和b之间来回以恒定的速度来回跑,路上没有停留,dudi的速度是gani的1.5倍,dudi从a往b跑,gani从b往a跑,他们同时出发,第一次相遇时在距离b点800米的地方,问他们第二次相遇在距离点的什么地方?
答：设gani的速度为x,dudi的速度为1.5x,第一次相遇所用时间为t1,第二次相遇所欲时间为t2 ,ab的距离为y.
则1.5xt1+xt2=y
xt1=800 所以y=2000m,gani的速度x=800/t1.dudi的速度1.5x=1200/t1
假设1：gudi到达b点后追上gani,
则800+800/t1*t2=1200/t1*t2 -800 所以t2=4t1 则xt2=3200m>1200m 假设不成立
假设2：两人到达ab殿后返回时相遇.
则1200/t1*t2+800/t1*t2=4000 所以t2=2t1,则t2=2t1=1600>1200且1年前查看全部
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