in(5x^3+x)/in(x^7+4x^2+1)求极限

一缕孤云2022-10-04 11:39:542条回答

in(5x^3+x)/in(x^7+4x^2+1)求极限
X趋近于无穷

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情定天崖 共回答了13个问题 | 采纳率100%
lim(x->∞) ln(5x^3+x)/ln(x^7+4x^2+1) (∞/∞)
=lim(x->∞) (x^7+4x^2+1)(15x^2+1)/[(5x^3+x)(7x^6+8x)]
=lim(x->∞) (1+4/x^5+1/x^7)(15+1/x^2)/[(5+1/x^2)(7+8/x^5)]
=15/35
=3/7
1年前
434434 共回答了6555个问题 | 采纳率
in(5x^3+x)/in(x^7+4x^2+1)求极限
=lim (x->∞)[ (15x^2+1)/(5x^3+x)]/[(7x^6+8x)/(x^7+4x^2+1)]
=lim (x->∞)[ (15x^2+1)(x^7+4x^2+1)/(5x^3+x)(7x^6+8x)]
=lim (x->∞)[ (15+1/x^2)(1+4/x^5+1/x^7)/(5+1/x^2)(7+8/x^5)]
=15×1/(5×7)
=3/7
1年前

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