4道因式分解.①4x²+2x+y+y²+4xy②x²-y²+4y-1③16x

九狐宝宝2022-10-04 11:39:542条回答

4道因式分解.
①4x²+2x+y+y²+4xy
②x²-y²+4y-1
③16x²-24xy-1+9y²
④4x²-16xy+4y²-6x+6y

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gangtse 共回答了21个问题 | 采纳率76.2%
①4x²+2x+y+y²+4xy
= 4x²+4xy+y²+2x+y
= (2x+y)²+2x+y
= (2x+y)(2x+y+1)
②抄错题了,应为x²-4y²+4y-1
x²-4y²+4y-1
= x²-(2y-1)²
= (x+2y-1)(x-2y+1)
③16x²-24xy-1+9y²
= 16x²-24xy+9y²-1
= (4x-3y)²-1
= (4x-3y+1)(4x-3y-1)
④抄错题了,应为4x²-8xy+4y²-6x+6y
4x²-8xy+4y²-6x+6y
=2(x²-2xy+y²)-6(x-y)
= 2(x-y)²-6(x-y)
= 2(x-y)(x-y-3)
1年前
xwy849 共回答了5510个问题 | 采纳率
①4x²+2x+y+y²+4xy
=4x²+4xy+y²+2x+y
=(2x+y)²+(2x+y)
(2x+y)(2x+y+1)
②x²-y²+4y-1
不能分解
换一个x²-y²+4y-4
=x²-(y-2)²
=(x+y...
1年前

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