若（3x-y+5）²+√2x-y+3=0,求x-y的值

6stnubbk2022-10-04 11:39:541条回答

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穿上aa 共回答了13个问题 | 采纳率84.6%: （3x-y+5）²+√2x-y+3=0,
3x-y+5 =0 ①
2x-y+3 = 0 ②
①-② x+2 = 0
x = -2
y = 3x+5 = -6+5 = -1
x-y的值
= -2 +1
= -1; 1年前

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