1/(log6^3)*1/logx^6 这个怎么化简?

原式= 1/[(ln2 /ln6)*（ln6/lnx）]
=1/(logx^2)
=log2^x
【loga^b=lna/lnb】
请选为满意答案

1/(log6^3)*1/logx^6
=1/(log6^3)*log6^x(换底公式得)
=log6^x/log6^3
=log3(x)

1/（log6^3）*1/logx^6
=1/(log6^3)*log6^x
=log6^x/log6^3
=log6^(x-3)