(-3a^2-9a^3b+12a^4b^2)/(-3a^2)=

snowying2022-10-04 11:39:541条回答

(-3a^2-9a^3b+12a^4b^2)/(-3a^2)=
RT

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(-3a^2-9a^3b+12a^4b^2)/(-3a^2)
=1+3ab-4a²b²
=-(4ab+1)(ab-1)
1年前

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15(x-y)^7除以5/6(x-y)^2=25/2(x-y)^5
(-3a^2-9a^3b+12a^4b^2)除以(-3a^2)=1+3ab+4(a^2)(b^2)=(4ab+1)(1-ab)
16(2m-n)^(p+2)除以[-4(2m-n)^(p-1)]=-4(2m-n)^3