(4a-3b+5c)(4a+3b+5c)

(4a-3b+5c)(4a+3b+5c)
=[（4a+5c)-3b][（4a+5c)+3b]
=（4a+5c)²-9b²
=16a²+40ac+25c²-9b²

解: (4a-3b+5c)(4a+3b+5c)
=[(4a+5c)-3b][(4a+5c)+3b]
=(4a+5c)²-(3b)²
=16a²+40ac+25c²-9b²
=16a²-9b²+25c²+40ac
祝你学习进步,如有不明可以追问.同意我的答案请采纳,O(∩_∩)O谢谢

(4a-3b+5c)(4a+3b+5c)
=(4a+5c-3b)(4a+5c+3b)
=(4a+5c)²-(3b)²
=16a²+40ac+25c²-9b²

(4a-3b+5c)(4a+3b+5c)
=[(4a+5c)-3b][(4a+5c)+3b]
=(4a+5c)²-(3b)²
=16a²+40ac+25c²-9b²