若分式2x+1/x^2-4x+3为非负数,求x的取值范围.

(2x+1)/(x^2-4x+3)>=0
(2x+1)/(x-3)(x-1)>=0
(2x+1)(x-3)(x-1)>=0且(x-3)(x-1）≠0
{x|-1/2

以后写试子要规范加括号。原式可化为(2x+1)(x-3)(x-1)>=0解得{x|x>=3或1>=x>=-1/2}