若|a-1|+4b^2+4b+1=0,则a^12-b^4=

即|a-1|+(2b+1)²=0
所以a-1=0,2b+1=0
a=1,b=-1/2
所以原式=1^12-(-1/2)^4
=1-1/16
=15/16

|a-1|+4b^2+4b+1=|a-1|+(2b+1)^2=0
a=1,b=-1/2
a^12-b^4
=1-1/16
=15/16