求微分方程2dx-(e^y+x)dy=0的通解

1)1阶微分方程
2)y=x^3-1
先对3x^2微分,得y=x^3-C,将点（1,0）带入,得C=1
考试加油哟!

yy''=y'^2+y^2
y'=dy/dx=p
y''=dp/dx=(dp/dy)(dy/dx)=pdp/dy
ypdp/dy=p^2+y^2
(y/2)dp^2=p^2dy+y^2dy
p^2=u
ydu/2=udy+y^2dy
u=vy du=vdy+ydv
y*(vdy+ydv)=2vydy+2y^2dy
y^2dv=vydy+2y^2dy
ydv=vdy+2ydy
ydv-vdy=2ydy
d(v/y)=2dy/y
v/y=2ln|y|+C
v=2yln|y|+Cy
u=vy=2y^2ln|y|+Cy^2
p^2=(2y^2ln|y|+Cy^2)
p=-y√(2ln|y|+C)
dy/dx=-y√(2ln|y|+C)
dy/dx和y=-x+1相切,y'(0,1)=-1
-1=-1√(2ln1+C)
C=1
dy/dx=-y√(2ln|y|+1)
dy/y√2ln|y|+1)=-dx
√(2ln|y|+1)=-x+C0
x=0,y=1,
C0=1
特解√(2ln|y|+1)=-x+1