(1-x)(1+x+xˇ2+...+xˇ98+xˇ99)

zerolove0002022-10-04 11:39:541条回答

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水问 共回答了18个问题 | 采纳率83.3%
(1-x)(1+x+x^2+...+x^98+x^99)
=(1-x)(1-x^100)/(1-x)
=1-x^100
1年前

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