4.75x4又3/4+4有3/4+4又3/4x4又1/4= 3/4x58+58除以4-64x1/4= 73.8除以9+7

虞四2022-10-04 11:39:541条回答

4.75x4又3/4+4有3/4+4又3/4x4又1/4= 3/4x58+58除以4-64x1/4= 73.8除以9+73.8除以1又1/8=
666.66x7778+333.33x4444=
(1+1/2+1/3+1/4+1/5)x(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)x(1/2+1/3+1/4+1/5)= 用简便算法哦

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andyzham 共回答了18个问题 | 采纳率100%
.75x4又3/4+4有3/4+4又3/4x4
=(75+1+4)*4又3/4
=80*4+80*3/4
=320+60
=380
3/4x58+58除以4-64x1/4
=1/4*58*3+1/4*58-64*1/4
=1/4*(164+58-64)
=1/4*158
=39.5
73.8除以9+73.8除以1又1/8
=73.8*1/9+73.8*8/9
=73.8*(1/9+8/9)
=73.8
666.66x7778+333.33x4444
=666.66*7778+666.66*2222
=666.66*(7778+2222)
=666.66*10000
=6666600
(1+1/2+1/3+1/4+1/5)x(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)x(1/2+1/3+1/4+1/5)
=(1/2+1/3+1/4+1/5+1/6)+(1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1/2+1/3+1/4+1/5)-(1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5+)
=0
1年前

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