输入任意日期，程序计算并输出100天后的日期。（要考虑闰年、跨月、跨年的情况，需要用到数组的知识)#include<stdio.h>main(){ int year,month,day,i; int DOM[13]={0,31,28,31,30,31,30,31,30,31,30,31,30}; printf("year,month,day="); scanf("%d,%d,%d",&year,&month,&day); if(((year%4==0)&&(year%100!=0))||(year%400==0)) DOM[2]=29; if((month<1)||(month>12)||(day>DOM[month])) printf("你输入的数据有错误，请重新输入:
"); else { for(i=1;i<=100;i++) { day+=1; if(day>DOM[month]) { month+=1; day=1; if(month>12) { year+=1; month=1; } if(((year%4==0)&&(year%100!=0))||(year%400==0)) DOM[2]=29; else DOM[2]=28; } } printf("100天后的日期是:%d-%d-%d
",year,month,day); }}
